When x<span> approaches to </span><span>+∞</span><span> the function </span><span>e^<span>3x</span></span><span> becomes much bigger then </span><span>e^<span>−3x</span></span><span>, which obviously means that </span><span>e^<span>−3x</span></span><span> can be neglected in both numerator and denominator.
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Here's how I figured this out:
</span><span>lim <span>x →+∞ </span></span>= (<span><span><span>e^(<span>3x))</span></span>− (<span>e^(<span>−3x)) / (</span></span></span><span><span>e^<span>3x)) </span></span>+ (<span>e^(<span>−3x)) </span></span></span></span>= <span>lim <span>x → +∞ </span></span><span><span>e^<span>3x / </span></span><span>e^<span>3x </span></span></span>= 1
Step-by-step explanation:
If the B is the middle of the segment AC,
AC= AB+BC
AC=7+12= 19.
If I'm wrong, correct me please. I would be pleased.
You would get 89/21 and then for a mixed number 4& 5/21
2.4080 meters.
Remember that the definition of work is force over distance. And that the gravitational potential energy that the turtle has will exactly match the work performed in lifting it. So have the following variables
Mass = 860.24 kg
Work = 20320.7 J = 20320.7 kg*m^2/s^2
Gravitational acceleration = 9.81 m/s^2
And we wish to get an answer in meters. So we need to multiply and divide the three numbers we have with all their related units and derive an answer with the unit of m. We can cancel out most of the units by dividing the work by the gravitational acceleration, so
20320.7 kg*m^2/s^2 / 9.81 m/s^2 = <span>
<span>2071.427 kg*m
Now we can cancel out the kg unit by dividing by the mass of the turtle. So
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2071.427 kg*m / 860.24 kg = </span><span>
<span>2.407964 m
Rounding to 5 significant figures gives 2.4080 meters.
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