Something to remember is how to multiply terms with same bases, but different exponents:
Essentially, we add the exponents.
Using the information above, we can find our answer:
Our answer is 
, or A.
Answer:
because base angle of isoscels triangle is congurent.
if one base is right angle then both base be rightangle.
Answer: The gradient of the line passing through is 3, thus the equation of the line becomes y=3x-4.
Step-by-step explanation: The parallel lines gradients that have similar gradients, so now we have the gradient of 3 because its similar to the other gradient. To get the equation of the line we use this equation: y=mx+c, we have to substitute the x and y to get the constant c.
5=3(3)+c
c= -4
y=3x+c
This is only my opinion. I could be wrong.
My guess is:
Somebody else used that book before you, maybe last year or
the year before, and it was somebody who didn't mind writing
in his book.
One day he didn't have time to write down the homework in his
assignment notebook, so he just circled the homework problems
in his textbook.
Answer:
The last equation x2 - 2x -4 = 0
has solution (x - 1)^2 - 5 = 0, x = 1 + root(5) or x = 1 - root(5)
Step-by-step explanation:
If a quadratic function has roots 1 and 5
f(x) = (x -1)(x- 5)
f(x) = x^2 - 6x + 5
Unless you meant. -4 and 6 ?
g(x) = (x + 4)(x - 6)
g(x) = x^2 -2x -24
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Or did you mean x = 1 and x =4 ?...
x^2 + 2x + 4 = 0 : complete square x^2 + 2x + 1 + 3 = 0, (x+1)^2 + 3 = 0
x^2 - 2x + 4 = 0 : complete square: (x -1)^2 + 3 = 0
0x^2 + 2x - 4 = 0, 2x - 4 = 0, x = 2
x^2 - 2x - 4 = 0 becomes: x^2 - 2x + 1 - 1 -4 = 0 ; (x - 1)^2 - 5 = 0
