Answer:
- A: 24,500
- B: 11,800
- C: 12,700
Step-by-step explanation:
Since the number of A seats equals the total of the rest of the seats, it is half the seats in the stadium: 49000/2 = 24,500.
The revenue from those seats is, ...
24,500×$30 = $735,000
so the revenue from B and C seats is ...
$1,246,800 -735,000 = $511,800
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We can let "b" represent the number of B seats. Then there are 24500-b seats in the C section and the revenue from those two sections is ...
24b +18(24500-b) = 511800
6b = 70,800 . . . . . . . . . . . . . . . subtract 441000, collect terms
b = 70,800/6 = 11,800 . . . . . . . seats in B section
24,500 -11,800 = 12,700 . . . . . seats in C section
There are 24500 seats in Section A, 11800 seats in Section B, and 12700 seats in Section C.
Answer:
<u>D.10x+6=15</u>
Step-by-step explanation:
Answer:
10 + -6
Step-by-step explanation:
add them up to 4 and multiply to -60
Answer:
−5+11i
Step-by-step explanation:
(3+6i)−(8−5i)
Subtract 8−5i from 3+6i by subtracting the corresponding real and imaginary parts.
3−8+(6−(−5))i
Subtract 8 from 3. Subtract −5 from 6.
−5+11i
