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Leni [432]
2 years ago
13

Find the hypotenuse of a triangle that has an 8 cm width and a height of 12 cm.

Mathematics
1 answer:
anygoal [31]2 years ago
4 0

Answer:14

Step-by-step explanation:

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Please help I will mark brainlyest​
IgorLugansk [536]

Answer:

C.  x^5/2 + 6x^3/2 + 1.

Step-by-step explanation:

(x^3 + 6x^2 + x^1/2) / x^1/2

= x^(3 - 1/2) + 6 x(2-1/2) + 1

= x^5/2 + 6x^3/2 + 1.

3 0
3 years ago
What is the quotient?<br> (-3)2<br> w<br> col- co<br> 9<br> 9<br> CO
slavikrds [6]

Answer:

The answer will be 1/9

Step-by-step explanation:

any non zero expression will always be 1. you now have evaluate the powe (-3)^2 which will be 9. Answer should be 1/9. Good Luck!

3 0
3 years ago
How Do You Know How Many Places Are In Fifty Million Without Writing The Number In Standard Form
BartSMP [9]
Fifty million has 8 places
7 0
3 years ago
Chris made his aunt a garden. The width is 7 2/5 ft and the length is 5 1/2 ft. What is the area of the garden?
pishuonlain [190]

Answer:

Hello! if Chris garden is a square shape then the answer is 40 7/10 in fraction form or 40.7 in decimal form

6 0
2 years ago
Use the following function to find the value of each operation.
Murljashka [212]
<h2>Evaluating Composite Functions</h2><h3>Answer:</h3>

w(f(m(2))) = 593

<h3>Step-by-step explanation:</h3>

We can write how w(f(m(x))) will be defined but that's too much work and it's only useful when we are evaluating w(f(m(x))) with many inputs.

First let's solve for m(2) first. As you read through this answer, you'll get the idea of what I'm doing.

Given:

m(x) = -4x +1

Solving for m(2):

m(2) = -4(2) +1 \\ m(2) = -8 +1 \\ m(2) = -7

Now we can solve for f(m(2)), since m(2) = -7, f(m(2)) = f(-7).

Given:

f(x)=3x-1

Solving for f(-7):

f(-7)=3(-7)-1 \\ f(-7) = -21 -1 \\ f(-7) = -22

Now we are can solve for w(-22). By now you should get the idea why w(f(m(2))) = w(-22).

Given:

w(x) = x^2 -5x -1

Solving for w(-22):

w(-22) = (-22)^2 -5(-22) -1 \\ w(-22) = 484 -5(-22) -1 \\ w(-22) = 484 +110 -1 \\ w(-22) = 593

8 0
2 years ago
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