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3 years ago

The graph represents this system of equations.

Mathematics

1 answer:

bonufazy [111]3 years ago

5 0

Answer:

The answer to your question is (1, -2)

Step-by-step explanation:

See the graph below, in the graph, the solution is circled (1, -2). The solution is the point where the lines cross.

To check the answer, let's solve the system using algebra.

y = 2x - 4

y = 1 - 3x

2x - 4 = 1 - 3x

2x + 3x = 1 + 4

5x = 5

x = 5/5

x = 1

Find y by substitution

y = 2(1) - 4

y = 2 - 4

y = -2

Solution

(1, -2)

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If the area of a right triangle is 9/16 sq. ft. and the height is 3/4 ft, write an equation that relates the area to the base,b,

Rudik [331]

Answer:

Base = 1.5 ft

Step-by-step explanation:

Area = ½ × base × height

9/16 = ½ × base × 3/4

9/16 = 3/8 × base

base = 9/16 × 8/3

base = 3/2

base = 1½ ft

5 0

3 years ago

An electric bulb is sold in a box measuring 5 cm by 4 cm by 4 cm. If the shopkeeper receives them in a carton measuring 50 cm by

katen-ka-za [31]

Answer:

250

Step-by-step explanation:

Bulb box and carton both are of cuboidal shape.

For bulb box the dimensions are:

l = 5 cm, w = 4 cm, h = 4 cm

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$\implies V_{Bulb\: box} =5(4)(4)$

$\implies V_{Bulb\: box} =80\: cm^3$

For Carton the dimensions are:

l = 50 cm, w = 20 cm, h = 20 cm

$V_{Carton} =lwh$

$\implies V_{Carton} =50(20)(20)$

$\implies V_{Bulb\: box} =20,000\: cm^3$

To find the number of bulbs packed in the carton, divide the $V_{Carton}$ by $V_{Bulb\: box}$

$Number \:of \:bulbs =\frac{V_{Carton}}{V_{Bulb\: box}}$

$\implies Number \:of \:bulbs =\frac{20,000}{80}$

$\implies Number \:of \:bulbs = 250$

So, 250 bulbs will be packed in one carton.

3 0

2 years ago

Cifrele romane de la 1 pana 100 romani pls

Kamila [148]

Sorry I don’t understand 1-100=99 sorry

8 0

3 years ago

Function: y = x^2+ 5x - 7 Vertex:( Solutions:( and

tino4ka555 [31]

Answer:

Vertex: $(-\frac{5}{2} , -\frac{53}{4})$

Solutions: (0,-7), (1, -1), (2, 7)

I hope this helps!

8 0

3 years ago

What is the graph of this equation

OverLord2011 [107]

Answer:

Look at attached image

Step-by-step explanation:

8 0

4 years ago