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stealth61 [152]
3 years ago
5

Buck drove 220 miles in 5 hours. What was his average rate of speed?

Mathematics
2 answers:
iris [78.8K]3 years ago
8 0
Let
<em>Total distance = d = 220 miles</em>
<em>Total time = t = 5 hours</em>
<em>Average speed = ?</em>

<em>The required formula to find average rate of speed is </em>

<em>avg speed = d / t = 220 / 5 </em>

<em>average speed = 44 miles / hour</em>

luda_lava [24]3 years ago
4 0

220/5=44km/h because speed = distance/time
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Answer:

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but we will find sample size "n"

\sqrt{n}  = \frac{z_{a} S.D}{maximum error}

Squaring on both sides , we get

n  = (\frac{z_{a} S.D}{maximum error})^2

Given 99% confidence interval (z value) = 2.56

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n  = (\frac{z_{a} p(1-p)}{maximum error})^2

n≤ (\frac{2.56X\frac{1}{2} }{0.02}) ^{2}    ( here S.D = p(1-p) ≤ 1/2

on simplification , we get n = 4225

<u>Conclusion</u>:

The sample size of two samples is  n = 4225

<u>verification</u>:-

We will use maximum error formula = \frac{z_{a} S.D}{\sqrt{n} } = \frac{2.56 1/2}{\ \sqrt{4225} }  = 0.0196

substitute all values and simplify we get maximum error is 0.02

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