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hoa [83]
2 years ago
7

In a class of 55 21 study physics 24 study geography and 23 study economics and physics. if x students study all three subjects

and 2x study non of the subjects find
1 the value of x
2 the number of students that study only physics
3 number of students that study only 2 subjects
solve usind venn diagram
Mathematics
1 answer:
Rus_ich [418]2 years ago
3 0

The total number of students who studied only two subjects is 13.

The given parameters:

  • <em>Total number of students, n = 55 </em>
  • <em>Number of physics students = 21</em>
  • <em>Number of geography students = 24</em>
  • <em>Number of economics students = 23</em>
  • <em>Number of students for the 3 subjects, = x</em>
  • <em>Number of students who studied non = 2x</em>

The number of students who studied only two subjects can be determined by applying overlapping three sets formula as shown below;

Total = n(phy) + n(geo) + n(econ) + n(none)- n(double) - 2(all \ subjects)\\\\55 = 21 + 24 + 23 + 2x-n(double) - 2(x)\\\\55 =  68- n(double)\\\\n(double) = 68-55\\\\n(double) = 13

Thus, the total number of students who studied only two subjects is 13.

Learn more about overlapping three sets here:  brainly.com/question/2041029

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Match the parabolas represented by the equations with their foci.
Elenna [48]

Function 1 f(x)=- x^{2} +4x+8


First step: Finding when f(x) is minimum/maximum
The function has a negative value x^{2} hence the f(x) has a maximum value which happens when x=- \frac{b}{2a}=- \frac{4}{(2)(1)}=2. The foci of this parabola lies on x=2.

Second step: Find the value of y-coordinate by substituting x=2 into f(x) which give y=- (2)^{2} +4(2)+8=12

Third step: Find the distance of the foci from the y-coordinate
y=- x^{2} +4x+8 - Multiply all term by -1 to get a positive x^{2}
-y= x^{2} -4x-8 - then manipulate the constant of y to get a multiply of 4
4(- \frac{1}{4})y= x^{2} -4x-8
So the distance of focus is 0.25 to the south of y-coordinates of the maximum, which is 12- \frac{1}{4}=11.75

Hence the coordinate of the foci is (2, 11.75)

Function 2: f(x)= 2x^{2}+16x+18

The function has a positive x^{2} so it has a minimum

First step - x=- \frac{b}{2a}=- \frac{16}{(2)(2)}=-4
Second step - y=2(-4)^{2}+16(-4)+18=-14
Third step - Manipulating f(x) to leave x^{2} with constant of 1
y=2 x^{2} +16x+18 - Divide all terms by 2
\frac{1}{2}y= x^{2} +8x+9 - Manipulate the constant of y to get a multiply of 4
4( \frac{1}{8}y= x^{2} +8x+9

So the distance of focus from y-coordinate is \frac{1}{8} to the north of y=-14
Hence the coordinate of foci is (-4, -14+0.125) = (-4, -13.875)

Function 3: f(x)=-2 x^{2} +5x+14

First step: the function's maximum value happens when x=- \frac{b}{2a}=- \frac{5}{(-2)(2)}= \frac{5}{4}=1.25
Second step: y=-2(1.25)^{2}+5(1.25)+14=17.125
Third step: Manipulating f(x)
y=-2 x^{2} +5x+14 - Divide all terms by -2
-2y= x^{2} -2.5x-7 - Manipulate coefficient of y to get a multiply of 4
4(- \frac{1}{8})y= x^{2} -2.5x-7
So the distance of the foci from the y-coordinate is -\frac{1}{8} south to y-coordinate

Hence the coordinate of foci is (1.25, 17)

Function 4: following the steps above, the maximum value is when x=8.5 and y=79.25. The distance from y-coordinate is 0.25 to the south of y-coordinate, hence the coordinate of foci is (8.5, 79.25-0.25)=(8.5,79)

Function 5: the minimum value of the function is when x=-2.75 and y=-10.125. Manipulating coefficient of y, the distance of foci from y-coordinate is \frac{1}{8} to the north. Hence the coordinate of the foci is (-2.75, -10.125+0.125)=(-2.75, -10)

Function 6: The maximum value happens when x=1.5 and y=9.5. The distance of the foci from the y-coordinate is \frac{1}{8} to the south. Hence the coordinate of foci is (1.5, 9.5-0.125)=(1.5, 9.375)

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3 years ago
Find all solutions for a triangle with a = 14, b= 12, and B = 90°.
ziro4ka [17]

Answer:

No solution.

Step-by-step explanation:

Given

a = 14; b= 12; B = 90^\circ

Required

Find all possible solutions

If B = 90^\circ, then the triangle is right-angled and the hypotenuse is at b

Given that a = 14; b= 12;

This implies that a > b

In a right-angled triangle, the hypotenuse (side b) is the longest.

Since this is not true for the given sides, then the triangle has no solution.

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Two of them are drawn simultaneously from a deck of 48 cards.
Elina [12.6K]

The required probability is
a) both are cups is 0.05

b) At least one cup is 0.19

c) One is a cup and the other is a sword is   0.06

<h3 /><h3>What is probability?</h3>

Probability can be defined as the ratio of favorable outcomes to the total number of events.

a) for both are cups

P= 12*11/48*47
p = 0.05

b) for  At least one cup
p = 12*36/48*47
p = 0.19

c) for One is a cup and the other is a sword
p = 12*12/48*47
p = 0.06

Thus, the required probability is 0.05, 0.19, 0.06

Learn more about probability here:

brainly.com/question/14290572

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2 years ago
What is the area of this triangle in the coordinate plane?
Mars2501 [29]

Answer:

6 units

Step-by-step explanation:

7 0
3 years ago
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Find the area of the shaded regions below. Give your answer as a completely simplified exact value in terms of π (no approximati
Lera25 [3.4K]

Answer:

  (36π -72) cm²

Step-by-step explanation:

The area of a segment that subtends arc α (in radians) is given by ...

  A = (1/2)r²·(α - sin(α))

Here, you have r = 12 cm and α = π/2 radians, so the area of the segment is ...

  A = (1/2)(12 cm)²·(π/2 -1) = (36π -72) cm²

4 0
4 years ago
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