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OLEGan [10]
3 years ago
13

Solve the following logarithmic equations. log[(x^2 + 2x − 3)^4] = 0

Mathematics
1 answer:
saw5 [17]3 years ago
4 0

Answer:

The solutions are x = 1.24 and x = -3.24

Step-by-step explanation:

Hi there!

First, let´s write the equation:

log[(x² + 2x -3)⁴] = 0

Apply the logarithm property: log(xᵃ) = a log(x)

4 log[(x² + 2x -3)⁴] = 0

Divide by 4 both sides

log(x² + 2x -3) = 0

if log(x² + 2x -3) = 0, then  x² + 2x -3 = 1 because only log 1 = 0

x² + 2x -3 = 1

Subtract 1 at both sides of the equation

x² + 2x -4 = 0

Using the quadratic formula let´s solve this quadratic equation:

a = 1

b = 2

c = -4

x = [-b± √(b² - 4ac)]/2a

x =  [-2 + √(4 - 4(-4)·1)]/2 = 1.24

and

x = [-2 - √(4 - 4(-4)·1)]/2 = -3.24

The solutions are x = 1.24 and x = -3.24

Have a nice day!

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Hey Child.

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Therefore, x, the number of measures of music played, must be either 1 or 7.

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Step-by-step explanation:

Given

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Answer:

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Step-by-step explanation:

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Let s and a represent the number of students and adults respectively.

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Total ticket cost for the adults was ($8/adult)(a)

and for the students ($5/student)(s).

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