Answer:
Step-by-step explanation:
The determinant of a matrix is a special number that can be calculated from a square matrix.
...
To work out the determinant of a 3×3 matrix:
Multiply a by the determinant of the 2×2 matrix that is not in a's row or column.
Likewise for b, and for c.
Sum them up, but remember the minus in front of the b.
Answer:
The sample 2 has a lowest value of SE corresponding to the least sample variability.
Step-by-step explanation:
As the value of the sample means and standard deviations are not given, as similar question is found online from which the values of data is follows
The data is as attached with the solution. From this data
Sample 1 has a mean of 34 and a SE of 5
Sample 2 has a mean of 30 and a SE of 2
Sample 3 has a mean of 26 and a SE of 3
Sample 4 has a mean of 38 and a SE of 5
As per the measure of the sample variability is linked with the value of SE or standard error. Which is lowest in the case of sample 2 .
So the sample 2 has a lowest value of SE corresponding to the least sample variability.
Answer:
Two doesn’t equal 8. Theoretically, eight is the solution...
Step-by-step explanation:
Answer:
{ x | x ≥ 0 }
Step-by-step explanation:
Given,
There is a straight line started from (0, 9) and passes through (8, 1),
∵ In the coordinate plan, the values of x are arranged in increasing order to the right side of the y-axis,
Thus, the line is defined for all real values of x greater than 0,
Hence, Domain of the line = All real numbers greater than equal to 0,
i.e. { x | x ≥ 0 }
Thus, FIRST OPTION is correct.
Ok so, I assume this is 6 times 501
501
x 6
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3006
5 x 6 = 30
6 x 0 = 0
6 x 1 = 6