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3 years ago

Find the perimeter and area. (plz help with the answer)

Mathematics

1 answer:

ikadub [295]3 years ago

5 0

Hello!

PERIMETER:

To find the perimeter of the trapezoid, simply add all sides together.

15 + 5 + 9 + 5 = 34

The perimeter is $\boxed{ \bf 34~units.}$

____________________________________________________________

AREA:

A = $\frac{1}{2}$ h( $b_{1}$ + $b_{2}$ )

A = $\frac{1}{2}$ 4(9 + 15)

A = $\frac{1}{2}$ 4(24)

A = 2(24)

A = 48

The area of the trapezoid is $\boxed{ \bf 48~units^2}$

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iogann1982 [59]

Answer:

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Step-by-step explanation:

Hi there!

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Take the square root of both sides

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Therefore, the perimeter of the square is 44 inches. The perimeter of the rectangle is also 44 inches.

2) Determine the value of x

Use the formula for the perimeter of a rectangle:

$P=2(l+w)$ where l is the length and w is the width

Plug in 3x and x-2 as the length and width

$P=2(3x+(x-2))\\P=2(3x+x-2)\\P=2(4x-2)$

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$44=2(4x-2)$

Expand the parentheses

$44=8x-4$

Add 4 to both sides to isolate 8x

$44+4=8x-4+4\\48=8x$

Divide both sides by 8 to isolate x

$\frac{48}{8}=\frac{8x}{8} \\6=x$

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