F(x) = x - 2sinx
To find for what values of x graph has tangents we need to differentiate function f(x).
f'(x) = 1-2cosx
Now, if we want to have horizontal tangents we need to make function f'(x) equal to 0 because at minimum or maximum of function f(x) tangent is horizontal.
1-2cosx = 0
cosx = 1/2
x = pi/3 + 2*n*pi and
x = -pi/3 + 2*n*pi
Explanation: cosx = 1/2 for both 60° and -60°. If we make one circle cosx will be equal to 1/2 for 420 and 300 degrees. Writing degrees in radians (using pi) we can write formulas above where 2*pi represents one full circle and n is an integer which represents how many circles we made.
Answer:
By hypotenuse - side test (HL) the two triangles are congruent.
Step-by-step explanation:
In ∆ABC and ∆DCB
i) angleABC = angleDCB.....(each 90°)
ii) BC = BC .....( common side)
iii) AC = DB.....(given)
therefore by hypo-side test ∆ABC congruent ∆DCB
Answer:
128/2=64/2=32
Step-by-step explanation:
you really need a help with that ? you don't know how to divide by 2 ? and then to divide the result another time by 2 ?
not to mention that you could achieve that with in division by 4 (as this is the save as dividing by 2 and then again by 2).
putting such questions in here is a farce and a waste of time for the helping people.
