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Ostrovityanka [42]
2 years ago
12

The difference between the roots of the quadratic equation x^2−12x+q=0 is 2. Find q.

Mathematics
1 answer:
shtirl [24]2 years ago
5 0

Answer:

  • The required value of q is 35.

Step-by-step explanation:

Let α and β are the zeros of quadratic equation, x^2−12x+q=0.

  • It is given that difference between the roots of the quadratic equation x^2−12x+q=0 is 2.

Equation : α - β = 2

Equation : α + β = 12

Equation : αβ = q

We have to create an algebraic expression.

(a+b)² = (a-b)² + 4ab

(12)² = (2)² + 4q

144 = 4 + 4q

144 - 4 =4q

140=4q

q = 140/4

q = 35

Therefore, the required value of q is 35.

<u>Some information about zeroes of quadratic equation. </u>

  • Sum of zeroes = -b/a
  • Product of Zeroes = c/a
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Step-by-step explanation:

This can be translated to:

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Then we have that our function is:

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Now we can do a little table of it:

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f(1) = 2*(1 + 1) = 4

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3 years ago
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Now factor out y

(P - 6)y = qp - 7

Divide by P - 6 from both sides

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Step-by-step explanation:

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