Answer:
Step-by-step explanation:
<u>Quadrant I examples:</u>
<u>Quadrant II examples:</u>
<u>Quadrant III examples:</u>
<u>Quadrant IV examples:</u>
<span>The diagonals of a parallelogram bisect each other.
So we just equate the two equations BE and DE
2x^2 - x = x^2 + 6
2x^2 - x - x^2 - 6 = 0
x^2 - x - 6 = 0
This is quadratic eqn. So we obtain.
(x - 3) ( x + 2) = 0
Setting each to 0 and solving for x, we have that x = 3 and x = -2
So we have two possible values for BD.
But Since BE = DE then we can simply double each
If x = 3 BD = 2 (2(3)^2 - 3) = 2 ( 18 - 3) = 30 units
If x = - 2 BD = 2((-2)^2 -3 ) = 2 (8 - 3) = 10 units</span>
The factors of 189 are: 1, 3, 7, 9, 21, 27, 63, 189.
1 × 189 = 189
3 × 63 = 189
7 × 27 = 189
9 × 21 - 189
I have calculated it,The answer is 170 in^3
Hope it helps!
