1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
bulgar [2K]
3 years ago
6

The table shows the outputs y for different inputs x:

Mathematics
1 answer:
kirill [66]3 years ago
4 0
Part A:

For a table to be considered a function, every x-value must have one y-value. 
Each x-value in this table is unique, and has only one y-value, so this table does represent a function.

Part B:

Plug in 7 for every x in the relation:

2(7) + 13 = 14 + 13 = 27

The table's output when x = 7 is 11. Compare the two outputs:

11 < 27

The relation, 2x + 13, has a greater value when x = 7.

Part C:

Set the relation to equal 75:

2x + 13 = 75

Subtract 13 from both sides:

2x = 62

Divide both sides by 2 to get x by itself:

\boxed{x = 31}

The x value that produces an output of 75 will be 31.
You might be interested in
Evaluate the expression 4y/Yfor x=8 and y=0
jeyben [28]
To evaluate 4y/x for x=8 and y=0 we shall have:
4y/x=(4×0)/8
=0/8
=0
Answer; 0
8 0
3 years ago
Helppppp me find a equation for this lol
LUCKY_DIMON [66]

Answer: One POSSIBLE answer is (0,9)

Step-by-step explanation: This may look hard but it's actually super easy. All you have to do is substitute a value for x and see what you get as the y value. The first thing I would do is rearrange the equation so that the equation is in the format y = something. So the first thing you should do is subtract 6x from both sides of the equation and you should get -y=-6x+9. Right now, the y is being multiplied by -1, and to undo multiplication, you have to divide. So divide both sides of the equation by -1 (remember, what you do on one side of the equation, YOU HAVE TO DO THE SAME THING ON THE OTHER SIDE). So your new equation would be y=6x-9. Then, all you have to do is substitute a value for x and see what you get for y (x is basically the input and whatever you get for y is the output). S for example, let's say that x=0. So substitute a 0 in the equation wherever you see an x. So in this case, you would get y=(6x0)+9. Then you just simplify. So 6x0 is 0 and 0+9=9 So y=9

TO RECAP: Rearrange the equation so that the equation is in the format y = something. Then, input any number for x, and whatever you get for y is what you put in the brackets as your y value for your final answer.

Hope this helps!

6 0
3 years ago
Read 2 more answers
Helpppppp please please
GenaCL600 [577]
3/10=4/x
3x=10(4)
3x=40
x=13.33
8 0
3 years ago
Write the contrapositive of the conditional statement. Determine whether the contrapositive is true or false. If it is false, fi
zubka84 [21]

Answer: A converse statement is formed by exchanging the hypothesis and conclusion of the conditional.

Step-by-step explanation:

8 0
3 years ago
After 8 years, how much will brandon have saved in interest by consolidating the two balances? a. $581.76 b. $194.40 c. $256.32
Fantom [35]

Answer:

C

Step-by-step explanation:

7 0
2 years ago
Other questions:
  • Will mark brainliest please help! Ty
    5·2 answers
  • Multiply. <br> (3.5 x 10^-5) (3 x 10-10)
    10·1 answer
  • PLease help if u can✊​
    5·1 answer
  • U=\frac{a\pih^2a}{m} \int\limits^a_b {x} \, dx \pi d^3 x l w (x) l^4<br> evaluate it
    9·1 answer
  • What is 3 × 5 ÷ 27 +8 -2​
    14·2 answers
  • An important problem in industry is shipment damage. A windshield factory ships its product by truck and determines that it cann
    11·1 answer
  • Relay races called for 8 people on a team. There were 43 men and 34 women who wanted to race. How many teams could be formed ?ho
    10·1 answer
  • Please help:)) will give brainliest:)
    15·1 answer
  • The sun of three consecutive integers is 60 find the integers
    14·1 answer
  • Factorise :<br>ab(x^2 - y^2) + (a^2 - b^2)xy = 0​
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!