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alexdok [17]
3 years ago
9

Write the equation of the parallel line that passes through (0,-3)

Mathematics
1 answer:
Gemiola [76]3 years ago
5 0

Answer:

y = 1.2x - 3 (slope intercept form)

or

5y-6x = -15 (standard form)

Step-by-step explanation:

Two parallel lines have the same slope, which means that our line's slope, will also be 1.2.

we can use the formula to find the equation of the line:

y-y1 = m (x-x1)

y1 - y coordinate of a point on the line

x1 - x coordinate of the same point on the line

m - slope

 

and we get:

y+3 = 1.2 (x-0)

y = 1.2x - 3 (slope intercept form)

or

5y-6x = -15 (standard form)

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The factored form of polynomial P(x) shows only two of its roots. Assuming all of the
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(x/x+3)-(8/x+2)=(-13x-6)/(x^2+5x+6)​
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Answer:

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Step-by-step explanation:

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\dfrac{x}{x+3}-\dfrac{8}{x+2}=\dfrac{-13x-6}{x^2+5x+6}

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x\neq -2\ \text{and}\ x\neq -3

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\dfrac{x}{x+3}-\dfrac{8}{x+2}=\dfrac{-13x-6}{(x+2)(x+3)}\\ \\\dfrac{x(x+2)-8(x+3)}{(x+2)(x+3)}=\dfrac{-13x-6}{(x+2)(x+3)}\\ \\x(x+2)-8(x+3)=-13x-6\\ \\x^2+2x-8x-24=-13x-6\\ \\x^2+2x-8x+13x-24+6=0\\ \\x^2+7x-18=0\\ \\x^2+9x-2x-18=0\\ \\x(x+9)-2(x+9)=0\\ \\(x+9)(x-2)=0\\ \\x+9=0\ \text{or}\ x-2=0\\ \\x=-9\ \text{or}\ x=2

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3 years ago
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