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AlexFokin [52]
3 years ago
7

An engineer on the ground is looking at the top of a building. The angle of elevation to the top of the building is 46Á. The eng

ineer knows the building is 250 ft tall. What is the distance from the engineer to the base of the building to the nearest whole foot?
Mathematics
2 answers:
Doss [256]3 years ago
6 0
The engineer's distance from the building, the building's height and the engineer's line of sight form a right angle triangle.
Thus, we apply:
tan∅ = height/base
base = 250/tan(46)
base = 241.4 feet
So 241 feet
Simora [160]3 years ago
3 0
The horizontal distance, height of the building, and the line of sight are the sides of a right triangle. The horizontal distance can be computed using tangents.

 h = y / tan(angle)h = 250 / tan(46 deg)h = 241 ft.


I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

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