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miv72 [106K]
3 years ago
8

Easy 50 points, one multi choice question

Mathematics
2 answers:
scZoUnD [109]3 years ago
7 0

Answer:

The correct answer is D.

Step-by-step explanation:

kotegsom [21]3 years ago
6 0
D is the correct answer
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Please can someone help geometry honors
oee [108]

Answer: THE FIRT ANSWER IS (C) AND THE SECOND ANSWER IS (A)

Step-by-step explanation:LEMME GET BRAINLIEST PLS AND THANK YOU

7 0
3 years ago
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Hey can someone help me with this?? Im very confused and need this explained to me! Thank you so much!!
Over [174]

Answer:

( C ) ΔMLN ≅ΔTSR

Step-by-step explanation:

Okay I got you!

So if the triangle <u>str</u> was flipped and rotated the other way then you will see that they are similar. They are asking what other "pairs" could you do to make it equivalent. Since M = T then you got your first pair. Next you go to N and when you look at the shape you'll see it will be S. N=S. And the last one would be L=R. I hope I was helpful enough! uwu Try to draw them out it will be helpful!!

8 0
3 years ago
This is the range of sample statistics obtained when many samples are selected?
Leno4ka [110]
The range of sample statistics obtained when many samples are selected is a sampling distribution. A sampling distribution is also a probability distribution of the statistics obtained in the large number of samples drawn from a specific population. It also shows every possible result that the statistic can take in every possible sample from the population and how often will each results happens.
4 0
3 years ago
Use any of the methods to determine whether the series converges or diverges. Give reasons for your answer.
Aleks [24]

Answer:

It means \sum_{n=1}^\inf} = \frac{7n^2-4n+3}{12+2n^6} also converges.

Step-by-step explanation:

The actual Series is::

\sum_{n=1}^\inf} = \frac{7n^2-4n+3}{12+2n^6}

The method we are going to use is comparison method:

According to comparison method, we have:

\sum_{n=1}^{inf}a_n\ \ \ \ \ \ \ \ \sum_{n=1}^{inf}b_n

If series one converges, the second converges and if second diverges series, one diverges

Now Simplify the given series:

Taking"n^2"common from numerator and "n^6"from denominator.

=\frac{n^2[7-\frac{4}{n}+\frac{3}{n^2}]}{n^6[\frac{12}{n^6}+2]} \\\\=\frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{n^4[\frac{12}{n^6}+2]}

\sum_{n=1}^{inf}a_n=\sum_{n=1}^{inf}\frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{[\frac{12}{n^6}+2]}\ \ \ \ \ \ \ \ \sum_{n=1}^{inf}b_n=\sum_{n=1}^{inf} \frac{1}{n^4}

Now:

\sum_{n=1}^{inf}a_n=\sum_{n=1}^{inf}\frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{[\frac{12}{n^6}+2]}\\ \\\lim_{n \to \infty} a_n = \lim_{n \to \infty}  \frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{[\frac{12}{n^6}+2]}\\=\frac{7-\frac{4}{inf}+\frac{3}{inf}}{\frac{12}{inf}+2}\\\\=\frac{7}{2}

So a_n is finite, so it converges.

Similarly b_n converges according to p-test.

P-test:

General form:

\sum_{n=1}^{inf}\frac{1}{n^p}

if p>1 then series converges. In oue case we have:

\sum_{n=1}^{inf}b_n=\frac{1}{n^4}

p=4 >1, so b_n also converges.

According to comparison test if both series converges, the final series also converges.

It means \sum_{n=1}^\inf} = \frac{7n^2-4n+3}{12+2n^6} also converges.

5 0
3 years ago
A number increased by 4 is the same as 19 minus 2 times the number. (10 points) plss help tkssss
ohaa [14]

Step-by-step explanation:

x+4=19-2x

Im pretty sure Im right!

4 0
3 years ago
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