Answer:
After two seconds
h(2) = -16(2^2) + 115(2) + 19
h(2) = -64 + 115(2) +19
h(2) = 185
Let me know if this helps!
Number 3 is .4 i think just minus 1.2 - .8
Part A. Your model is as good as any. It is hard to tell if the label needs to include the descriptor (length = 12 ft, for example). Certainly your model is sufficient for Part B.
Part B. The total area is the sum of the areas of each of the 6 faces of the box. Opposite faces are the same area, so you have
A = 2(LW +WD +LD) = 2(LW +D(L +W))
Subsituting the given dimensions, you get
A = 2((12 ft)(6 ft) +(3 ft)(12 ft +6 ft))
A = 2(72 ft² +(3 ft)(18 ft))
A = 2(72 ft² +54 ft²) = 252 ft²
The least amount of paper required to cover the box is 252 ft².
Answer:The dragon fly can fly 35/12 miles
Step-by-step explanation:
Speed =distance / time
If the distance A dragonfly flies 7/8 of a mile
And
Time =3/10 of an hour.
Speed =7/ 8 ÷3/10 =7/ 8 x 10/3 =70/24 reducing to lowest term becomes 35/12 miles / hour
Now when the dragon fly flies in 1 hour, its distance covered becomes
Speed =distance / time
35/12 miles / hour=distance / 1
distance =35/12 miles
