Although the concept here is physics, the solution is technically just algebra. You have two situations that are related to each other which can be expressed in equation form. Actually, the equation is already given which is <span>7/12 w= 13 5/12. So, basically, all you have to do is solve for w.

Let's simplify 13 5/12 first into an improper fraction.You do this by multiplying the denominator with the whole number and adding to it the numerator. This will be your new numerator, The denominator would still be 12. So, this is equal to (12*13 + 5)/12 = 161/2. Then,

(7/12) w = 161/12

By cross multiplication,

7*12*w = 161*12
w = 161/7 = 23

Therefore, w = 23 pounds which is the weight of the object on Earth.

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8 0

3 years ago

A silo is constructed using a cylinder with a hemisphere on top. The circumference of the hemisphere and the circumference of th

givi [52]

1. The surface that will be exposed to the rain is the lateral surface of the cylinder and the hemisphere.

2. The lateral area of the cylinder is a rectangle with height equal to the height of the cylinder and width equal to the circumference of the base of the cylinder.

3. the circumference of the base = 2 $\pi$ r=2* $\pi$ *5=10 $\pi$
so the lateral area = 10 $\pi$ *h=10 $\pi$ *40=400 $\pi$ ( $ft^{2}$ )

4. The surface area of a sphere is $4 \pi r^{2}$
so the surface of the hemisphere = $\frac{1}{2} *4 \pi r^{2}=2 \pi (5)^{2}=50 \pi$ ( $ft^{2}$ )

5. Total area exposed = 450 $\pi$ $ft^{2}$

4 0

3 years ago

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PLS ANSWER NOW

lora16 [44]

You're answers are a bit jumbled up but here is the answer:
T for Two
B for Blue
M for Moon Roof
F for four
G for Gray
NM for No Moon Roof... so

TBM
TBNM
TGM
TGNM
FBM
FBNM
FGM
FGNM
8 Possibilities

6 0

3 years ago

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