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3 years ago

How much is 2 tenths in fifths

Mathematics

2 answers:

max2010maxim [7]3 years ago

6 0

$\frac{2}{10} \times \frac{1}{5} = \frac{1}{5} \times \frac{1}{5} = \frac{1}{25} = 0.04$

serg [7]3 years ago

3 0

Reasoning could also be used to prove that if 1/5 is 2 tenths (0.2), then 2/5 would be twice as much, or 4 tenths (0.4). Students could also divide each fifth of the rectangle into 2 equal parts to make 10 tenths

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I need help i don't understand

ioda

Answer:

so simple

its given that,

first given the answer

3 0

2 years ago

What is the integer for the sum -4 and the product -12

Valentin [98]

-4 multiplied by -12 would be 48

5 0

4 years ago

Rewrite 2x^2+13x+26/x+4 in the form q(x)+r(x)/b(x) . Then find q(x) and r(x).

natulia [17]

We are dividing the polynomial $2x^{2} +13x+26$ by x+4

notice that $2x^{2}$ is x times 2x,

so if we multiply (x+4) by 2x, which gives us $2 x^{2} +8x$ , we can 'separate' one $2 x^{2} +8x$ from $2x^{2} +13x+26$ to get the following simplification:

$\frac{2x^{2} +13x+26}{x+4}= \frac{ 2x^{2}+8 x}{x+4} + \frac{5x+26}{x+4}=2x+ \frac{5x+26}{x+4}$

similarly we notice that 5x is x times 5, so if we multiply (x+4) by 5, we get 5x+20 so we can rewrite

$\frac{5x+26}{x+4}= \frac{5x+20}{x+4}+ \frac{6}{x+4}=5+\frac{6}{x+4}$

$\frac{6}{x+4}$ can not be simplified any further since the degree of 6, is smaller than the degree of x+4

combining our work, we have:

$\frac{2x^{2} +13x+26}{x+4}=2x+5+\frac{6}{x+4}$

Answer:

q(x)= 2x+5
r(x)=6
b(x)=x+4

Remark: we can solve the problem by long division or the division algorithm as well.

6 0

4 years ago

Read 2 more answers

If (5x−2)^2=ax^2−bx+c, what is the value of a+c^2?

Nostrana [21]

Answer:

Step-by-step explanation: u first expand (5x-2)²

to get 25x²-20x+4

then by comparing it to ax²+bx=c

u get a=25 b=-20 and c=4

the u evaluate a+c²

25+4²

=41

3 0

4 years ago

Please help and show work!!

telo118 [61]

Let’s start by considering any 2 points falling on the line, the intercepts are the ones which come to my mind. Thus, the line 2x+3 will originally intersect the x- axis at (−32,0) and the y- axis at (0,3).

So, the basic insight is that on rotating the origin, the axes rotate. But the intercepts (their lengths) don’t change. The axis that is being intercepted will change, not the distance of intercepting points from the origin until our line is itself rotated. (Keep scribbling)

For the first case, we rotate the axes clockwise by a right angle. Now notice that the negative x-axis replaces the positive y-axis. So, our line now intercepts the negative x- axis at a distance 3 from the origin. Similarly, the negative y- axis replaces the negative x- axis. So, our line intersects the negative y- axis at distance 1.5 .

Therefore, the new intercepts are X(−3,0) and Y(0,−1.5). We can hence produce the new equation for our line in the slope- intercept form as

y=−x2−1.5 .

Similarly, you can imagine the other cases as axes rotation/replacement.

For 180∘, the equation would be y=2x−3 .

For 270∘, the equation would be y=−x2+1.5 .

7 0

3 years ago