2p+8p>-20 help please ☺️

What is the justification for each step in solving the inequality? −7(3+8x)+5x≤1−62x

dangina [55]

Distribute -7 because of math
-21-56x+5x≤1-62x
add like terms because you aint chaingin nothing
-21-51x≤1-62x
add 62x to both sides (addition property of equality, where a=a and b=b, a+b=a+b) and also (addative inverse, a+(-a)=0) that turns the -62x to 0
-21+11x≤1
add 21 to both sides (additiona proerty of equality and addativeinverse)
11x≤22
divide both sides by 11 (division property of equality, if a=a and b=b, then a/b=a/b)
x≤2

5 0

2 years ago

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a taxi driver makes $24.50 in an hour, but uses $6.75 worth of gas during that time. what will the driver's total earnings for t

Paladinen [302]

$24.50 - $6.75 = $17.75

4 0

3 years ago

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Solve <img src="https://tex.z-dn.net/?f=%5Csf%20%5Cdfrac%7B1%7D%7Bp%7D%20%2B%20%5Cdfrac%7B1%7D%7Bq%7D%20%2B%20%5Cdfrac%7B1%7D

Nostrana [21]

Answer:

$\displaystyle \begin{cases} \displaystyle {x} _{1} = - p \\ \displaystyle x _{2} = - q \end{cases}$

Step-by-step explanation:

we would like to solve the following equation for x:

$\displaystyle \frac{1}{p} + \frac{1}{q} + \frac{1}{x} = \frac{1}{p + q + x}$

to do so isolate $\frac{1}{x}$ to right hand side and change its sign which yields:

$\displaystyle \frac{1}{p} + \frac{1}{q} = \frac{1}{p + q + x} - \frac{1}{x}$

simplify Substraction:

$\displaystyle \frac{1}{p} + \frac{1}{q} = \frac{x - (q + p + x)}{x(p + q + x)}$

get rid of only x:

$\displaystyle \frac{1}{p} + \frac{1}{q} = \frac{ - (q + p )}{x(p + q + x)}$

simplify addition of the left hand side:

$\displaystyle \frac{q + p}{pq} = \frac{ - (q + p )}{x(p + q + x)}$

divide both sides by q+p Which yields:

$\displaystyle \frac{1}{pq} = \frac{ -1}{x(p + q + x)}$

cross multiplication:

$\displaystyle x(p + q + x) = - pq$

distribute:

$\displaystyle xp + xq + {x}^{2} = - pq$

isolate -pq to the left hand side and change its sign:

$\displaystyle xp + xq + {x}^{2} + pq = 0$

rearrange it to standard form:

$\displaystyle {x}^{2} + xp + xq + pq = 0$

now notice we end up with a quadratic equation therefore to solve so we can consider factoring method to use so

factor out x:

$\displaystyle x( {x}^{} + p ) + xq + pq = 0$

factor out q:

$\displaystyle x( {x}^{} + p ) +q (x + p)= 0$

group:

$\displaystyle ( {x}^{} + p ) (x + q)= 0$

by Zero product property we obtain:

$\displaystyle \begin{cases} \displaystyle {x}^{} + p = 0 \\ \displaystyle x + q= 0 \end{cases}$

cancel out p from the first equation and q from the second equation which yields:

$\displaystyle \begin{cases} \displaystyle {x}^{} = - p \\ \displaystyle x = - q \end{cases}$

and we are done!

3 0

2 years ago

It costs $100 to join a fitness center plus a monthly fee. You spent $700 last year at the fitness center. How much was the mont

Virty [35]

It cost $50 a month

Work: 700 - 100 = 600

600 / 12 = 50

Hope this helps!

6 0

3 years ago

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Julio bought 12 bulbs of jumbo garlic for $11.88. How many bulbs of jumbo garlic can Anjali buy if she has $3.96?

Molodets [167]

Answer:

Anjali can buy 4 bulbs of jumbo garlic if she has $3.96.

Step-by-step explanation:

To calculate how many bulbs of jumbo garlic Anjali can buy with $3.96, we must first calculate the unit rate of the jumbo garlic. Julio buying 12 bulbs of jumbo garlic for $11.88 can be represented as:

$\frac{11.88}{12}$

Divide the fraction by $\frac{12}{12}$ to calculate the unit rate:

$\frac{.99cents}{1bulb}$

So if each bulb of garlic costs $0.99, which we can think of as being $1.00 at the moment, we could figure that Anjali's $3.96 would be closer to $4 than it is to $3, so let's multiply the unit rate by $\frac{4}{4}$ :