Question

What is the solution to log2 (9x)- log2^3=3?

Answer 1

Answer:

x = $\frac{8}{3}$

Step-by-step explanation:

Using the rule of logarithms

log x - log y = log ($\frac{x}{y}$ )

$log_{b}$ x = n ⇒ x = $b^{n}$

Given

$log_{2}$ (9x) - $log_{2}$ 3 = 3

$log_{2}$ ($\frac{9x}{3}$ ) = 3

$log_{2}$ 3x = 3

3x = 2³ = 8 ( divide both sides by 3 )

x = $\frac{8}{3}$