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MissTica
3 years ago
14

The area of a rectangle is pool is (15x-9) square units. Factor 15x-9 to find possible dimensions of the pool

Mathematics
2 answers:
Darya [45]3 years ago
8 0
This is the concept of algebra, given that the area of a rectangular pool is (15x-9), the possible dimensions of the pool by factoring will be:
Area=length×width
Area=(15x-9)
factoring the above we get:
Area=3(5x-3)
therefore the possible dimension will be:
length=5x units
width=3 units
Art [367]3 years ago
5 0

Answer:

3 and (5x-3).

Step-by-step explanation:

The area of a rectangle is

Area=lenght \times width

It is given that the area of a rectangle is pool is (15x-9) square units.

We need to find the factors of (15x-9), to find the dimensions of the pool.

Area=15x-9

It can be rewritten as

Area=3\times 5x-3\times 3

It is clear that 3 is GCF.

Taking out GCF, we get

Area=3(5x-3)

Since the area of a rectangle is the product of its dimensions, therefore 3 and (5x-3) are dimensions of the pool.

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28 divided by 40 is 0.7 which equals 70 percent.

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3 years ago
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What is the answer?<br> xy = 30<br> and x + y = 18
drek231 [11]

from second equation y = 18-x so:-

x(18 - x) = 30

x^2 - 18x + 30 = 0

x = 16.14, 1.86


when x = 16.14 y = 18-16.14 = 1.86

when x = 1.86, y = 16.14


so one variable = 16.14 and the other = 1.86 Answer

3 0
3 years ago
6y+4−3y−7=3(y−1) How many solutions are for this?
Kryger [21]

Answer:

Infinite amount of solutions.

General Formulas and Concepts:

  • Order of Operations: BPEMDAS
  • Regular + Equality Properties

Step-by-step explanation:

<u>Step 1: Define equation</u>

6y + 4 - 3y - 7 = 3(y - 1)

<u>Step 2: Solve for </u><em><u>y</u></em>

  1. Combine like terms:                         3y - 3 = 3(y - 1)
  2. Distribute 3:                                       3y - 3 = 3y - 3
  3. Subtract 3y on both sides:               -3 = -3

Here we see that there will be infinite amount of solutions. We can plug in any number <em>y</em> and it will render the equation true.

8 0
2 years ago
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What is the area of this triangle ?
oee [108]

Answer:

Area of triangle is 9.88 units^2

Step-by-step explanation:

We need to find the area of triangle

Given E(5,1), F(0,4), D(0,8)

We will use formula:

Area\,\,of\,\,triangle =\sqrt{s(s-a)(s-b)s-c)} \\where\,\, s = \frac{a+b+c}{2}

We need to find the lengths of side DE, EF and FD

Length of side DE = a = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

Length of side DE = a = =\sqrt{(5-0)^2+(1-8)^2}\\=\sqrt{(5)^2+(-7)^2}\\=\sqrt{25+49}\\=\sqrt{74}\\=8.60

Length of side EF = b = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

Length of side EF = b = =\sqrt{(0-5)^2+(4-1)^2}\\=\sqrt{(-5)^2+(3)^2}\\=\sqrt{25+9}\\=\sqrt{34}\\=5.8

Length of side FD = c = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

Length of side FD = c = =\sqrt{(0-0)^2+(8-4)^2}\\=\sqrt{(0)^2+(4)^2}\\=\sqrt{0+16}\\=\sqrt{16}\\=4

so, a= 8.60, b= 5.8 and c = 4

s = a+b+c/2

s= 8.6+5.8+4/2

s= 9.2

Area of triangle==\sqrt{s(s-a)(s-b)s-c)}\\=\sqrt{9.2(9.2-8.6)(9.2-5.8)(9.2-4)}\\=\sqrt{9.2(0.6)(3.4)(5.2)}\\=\sqrt{97.5936}\\=9.88

So, area of triangle is 9.88 units^2

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Answer:

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