Answer:
the answer is 18 feet because that line in the middle of the triangle is half the size of AC
Answer:
The third picture
Step-by-step explanation:
Solve for x in both equations
2x<6
Divide both sides by 2:
x<3
3x+2>-4
Subtract 2 from both sides:
3x>-6
Divide both sides by 3:
x>-2
There is this trick you can use when x is on the left side of the equation to find out which way to shade in you graph. Keep in mind this is only for the left side, it will not work if your variable is on the right.
When the symbol is facing left < then shade left, imagine it is pointing which way to shade. x<3 is represented by the 3 picture on the left. When the symbol is facing right > then shade right, again it is pointing which way to shade. x>-2 is represented by the 3 picture on the right.
The circles are not filled in because the symbol is < and > rather than
. When it is greater than or equal to or less than and equal to (represented by the line under the symbol), then the circle is shaded in.
Answer: x ≥ 0
Step-by-step explanation:
First, let's define the symbols used:
a < x (this means that a is strictly smaller than x)
a > x (this means that a is strictly larger than x)
a ≤ x (this means that a is smaller than or equal to x)
a ≥ x (this means that a is larger than or equal to x)
Now we have the statement "x is no less than 0"
Then x can be equal to zero, or larger than zero, but never smaller than zero.
Looking at the symbols above, we know that we need to use:
x ≥ 0
(this is equivalent to the statement)
I can’t understand what you are asking for
Points Lying on the undefined curve are
x : 0 1 2 3 4
f(x): 3 7 29 87 199
Plotting the points on the coordinate plane
As you will see, the value of x increases , value of y increases .
It is not linear, because slope between two points is not same.
Neither quadratic nor cubic , it is not cutting x axis .
So, As value of x increases, value of y does not increases by a fixed quantity, but it increases.
So, option (D) Exponential ,Function word is the right word Describing these points.