Answer:
Jaime's wrong, becuase the distance(absolute value) from the point estimate to the lower bound is different than he distance from the upper bound to the point estimate.
Step-by-step explanation:
The distance(absolute value) from the point estimate to the lower bound must be the same as the distance from the upper bound to the point estimate.
The point estimate is 0.14.
Jaime
Jaime's interval has a lower bound of 0.049 and an upper bound of 0.191
upper - point = 0.191 - 0.14 = 0.051
point - lower = 0.14 - 0.049 = 0.091
Jaime's wrong, becuase the distance(absolute value) from the point estimate to the lower bound is different than he distance from the upper bound to the point estimate.
Mariya
Just to check.
Mariya's interval has a lower bound of 0.079 and an upper bound of 0.201.
upper - point = 0.201 - 0.14 = 0.061
point - lower = 0.14 - 0.079 = 0.061
Mariya has the same distances, so it is correct.
Answer:
Step-by-step explanation:
So in this example we'll be using the difference of squares which essentially states that: or another way to think of it would be: . So in this example you'll notice both terms are perfect squares. in fact x^n is a perfect square as long as n is even. This is because if it's even it can be split into two groups evenly for example, in this case we have x^8. so the square root is x^4 because you can split this up into (x * x * x * x) * (x * x * x * x) = x^8. Two groups with equal value multiplying to get x^8, that's what the square root is. So using these we can rewrite the equation as:
Now in this case you'll notice the degree is still even (it's 4) and the 4 is also a perfect square, and it's a difference of squares in one of the factors, so it can further be rewritten:
So completely factored form is:
I'm assuming that's considered completely factored but you can technically factor it further. While the identity difference of squares technically only applies to difference of squares, it can also be used on the sum of squares, but you need to use imaginary numbers. Because . and in this case a=x^2 and b=-4. So rewriting it as the difference of squares becomes: just something that might be useful in some cases.
Answer:
P40000 at 5%
P20000 at 4.5%
I am curious as to what the P stands for. Can you tell me?
Step-by-step explanation:
Let x = amt. invested at 5%
y = amt. invested at 4.5%
(1) x + y = 60000 (2) .05x + .045y = 2900
50x + 45y = 2900000
-45 times (1) <u>-45x - 45y = -2700000 </u>
5x = 200000
x = 40000
40000 + y = 60000
y = 20000
P40000 at 5%
P20000 at 4.5%
I am curious as to what the P stands for. Can you tell me?
Answer: rttgyt5tgot4h5uioyh
Step-by-step explanation:
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