Answer:
using quaderatic expression solving problems of algebraic expressions.
Step-by-step explanation:
no1.
take the smallest side to be x
and the longest side to be x-1/3
then expand the expression equating to 30.
then solve for x value
Let
ba--------> area of bases (<span>the two bases included</span>)
p---------> perimeter of the base
h--------> height of the prism
la-------> lateral area
we know that
[surface area]=2*[area of one base]+[perimeter of the base]*height
so
2*[area of one base]=ba
[surface area]=[ba]+[p]*h
and
the formula of lateral area is
[la]=[perimeter of the base]*height
[la]=[p]*h
therefore
[surface area]=[ba]+[la]
the answer is
[surface area]=[ba]+[p]*h
[surface area]=[ba]+[la]
Assuming "i" is an imaginary unit:
Oh, you're from connexus right? Well the answer is ounces
A quadratic equation cannot have one imaginary solution because of the discriminant enclosed in a radical. The discriminant, √(b² - 4ac), determines the nature of the roots and it can only be either 2 real roots, 1 real solution or 2 imaginary roots. Hope this answers the question.
