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3 years ago

5

A student needs to earn 80 points on the test in order to keep an A grade for the semester. Write an equation that represents th

e situation in terms of the number of correct answers

1 answer:

Annette [7]3 years ago

4 0

The most simple way is to get 8 questions right on a ten question test. 8q/10q = 80%.

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You are driving due north on the highway. Ahead, but off to the East, you see a tall tower. Sketch a graph or make a table showi

valentina_108 [34]

Answer:

The amount of speed you go will determine the graph but it should go closer and closer but then farther away because you drive past the tower

Step-by-step explanation:

3 0

3 years ago

I need someone to help me solve this

andrezito [222]

Answer:

see explanation

Step-by-step explanation:

Calculate C by adding corresponding components of A + B

C = $\left[\begin{array}{ccc}4\\-7.5\\\end{array}\right]$ + $\left[\begin{array}{ccc}-2.5\\5\\\end{array}\right]$

= $\left[\begin{array}{ccc}4-2.5\\-7.5+5\\\end{array}\right]$

= $\left[\begin{array}{ccc}1.5\\-2.5\\\end{array}\right]$

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3 years ago

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How do you get 85 tens in 23 ones in standard form ?

Andrew [12]

The answer is 873 hope this will help you.

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3 years ago

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A typical sugar cube has an edge length of 1.00 cm. Imagine you have a cubical box that contains a mole of sugar cubes, perfectl

alisha [4.7K]

Answer:

844368.7 m

Step-by-step explanation:

We are given that a typical sugar cube has an edge length of 1.00 cm.

We have to find the edge length of the box in meters.

Edge length of sugar cube=1 cm = $10^{-2}m$ ( $1 cm=\frac{1}{100}m$ )

Volume of a sugar cube= $side\times side\time side=(10^{-2})^3=10^{-6}m^3$

1 mole of sugar= $6.02\times 10^{23}units$

Volume of 1 unit= $10^{-6} m^3$

Volume of $6.02\times 10^{23}$ units= $6.02\times10^{23}\times 10^{-6}=6.02\times 10^{17} m^3$

Volume of box=1 mole of sugar= $6.02\times 10^{17} m^3$

Edge length of box= $\sqrt[3]{6.02\times 10^{17}}=844368.7 m$

6 0

2 years ago

Pentagon VWXYZ is shown on the coordinate grid. A student reflected pentagon VWXYZ across the x-axis to create pentagon V’W’X’Y’

pav-90 [236]

Reflecting across the x axis maintains the same x coordinate, but changes the sign of the y coordinate.

So, the transformation is

$(x,y)\mapsto (x,-y)$

7 0

3 years ago