I think we can use the identity sin x/2 = sqrt [(1 - cos x) /2]
cos x - sqrt3 sqrt ( 1 - cos x) /sqrt2 = 1
cos x - sqrt(3/2) sqrt(1 - cos x) = 1
sqrt(3/2)(sqrt(1 - cos x) = cos x - 1 Squaring both sides:-
1.5 ( 1 - cos x) = cos^2 x - 2 cos x + 1
cos^2 x - 0.5 cos x - 0.5 = 0
cos x = 1 , -0.5
giving x = 0 , 2pi, 2pi/3, 4pi/3 ( for 0 =< x <= 2pi)
because of thw square roots some of these solutions may be extraneous so we should plug these into the original equations to see if they fit.
The last 2 results dont fit so the answer is x = 0 , 2pi Answer
The vertex is 
Explanation:
The equation is 
To find the vertex, we need the equation in the form of 
Dividing each term by 2 in the equation 

Now, completing the square by adding and subtracting 1, we get,

The first three terms can be written as
,
![f(x)=2[(x+1)^{2}+\frac{1}{2} ]](https://tex.z-dn.net/?f=f%28x%29%3D2%5B%28x%2B1%29%5E%7B2%7D%2B%5Cfrac%7B1%7D%7B2%7D%20%20%5D)
Multiplying 2 into the bracket, we get,

This equation is of the form 
Now, we shall find the vertex 
Thus,
and 
Thus, the vertex is 
A = 1/2 or 0.5
My work is shown below. I hope this helped!! ^w^
Answer:
Option C is correct.
Constant of variation k = -0.5
Step-by-step explanation:
The direct variation says that:

then, the equation is of the form:
.....[1] where k is the constant of variation.
Given the table:
x f(x)=y
0 0
2 -1
4 -2
7 -3.5
Consider any values from the tables
x = 4 and y=f(x) = -2
Substitute these values in equation [1] we have;

Divide both sides by 4 we get;

Therefore, the constant of variation is, -0.5