Answer:
4032 different tickets are possible.
Step-by-step explanation:
Given : At a race track you have the opportunity to buy a ticket that requires you to pick the first and second place horses in the first two races. If the first race runs 9 horses and the second runs 8.
To find : How many different tickets are possible ?
Solution :
In the first race there are 9 ways to pick the winner for first and second place.
Number of ways for first place - 
Number of ways for second place - 
In the second race there are 8 ways to pick the winner for first and second place.
Number of ways for first place - 
Number of ways for second place - 
Total number of different tickets are possible is


Therefore, 4032 different tickets are possible.
Simplify 3/2t to 3t/2
16 - 2t = 3t/2 + 9
Multiply both sides by 2
32 - 4t = 3t + 18
Add 4t to both sideds
32 = 3t + 18 + 4t
Simplify 3t + 18 + 4t to 7t + 18
32 = 7t + 18
Subtract 18 from both sides
32 - 18 = 7t
Simplify 32 - 18 to 14
14 = 7t
Divide both sides by 7
14/7 = t
Simplify 14/7 to 2
2 = t
Switch sides
<u>t = 2</u>
Look Up Express 90 as the product of its prime number in orderAnd Read About Prime Numbers...
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