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inessss [21]
4 years ago
11

Create two whole number division problems that have a quotient of 9 and a remainder of 5

Mathematics
1 answer:
Sholpan [36]4 years ago
3 0
86 divides by 9 sequels to 9 Remainder 5 and 95 divided by 10 equals to 9 Remainder 5
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At a race track you have the opportunity to buy a ticket that requires you to pick the first and second place horses in the firs
rewona [7]

Answer:

4032 different tickets are possible.

Step-by-step explanation:

Given : At a race track you have the opportunity to buy a ticket that requires you to pick the first and second place horses in the first two races. If the first race runs 9 horses and the second runs 8.

To find : How many different tickets are possible ?

Solution :

In the first race there are 9 ways to pick the winner for first and second place.

Number of ways for first place - ^9C_1=9

Number of ways for second place - ^8C_1=8

In the second race there are 8 ways to pick the winner for first and second place.

Number of ways for first place - ^8C_1=8

Number of ways for second place - ^7C_1=7

Total number of different tickets are possible is

n=9\times 8\times 8\times 7

n=4032

Therefore, 4032 different tickets are possible.

8 0
3 years ago
16−2t=3/2t+9<br><br> Solve for T
Dmitrij [34]

Simplify 3/2t to 3t/2

16 - 2t = 3t/2 + 9

Multiply both sides by 2

32 - 4t = 3t + 18

Add 4t to both sideds

32 = 3t + 18 + 4t

Simplify 3t + 18 + 4t to 7t + 18

32 = 7t + 18

Subtract 18 from both sides

32 - 18 = 7t

Simplify 32 - 18 to 14

14 = 7t

Divide both sides by 7

14/7 = t

Simplify 14/7 to 2

2 = t

Switch sides

<u>t = 2</u>

6 0
4 years ago
2. Explain, in words, how you would solve this problem. Hint: you should get 1 point
makkiz [27]

Answer:

9-24=4(3)

-15=4×3

-15=12

7 0
3 years ago
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Express 90 as the product of its prime number in order
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Look Up Express 90 as the product of its prime number in orderAnd Read About Prime Numbers...

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