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Alla [95]
3 years ago
10

Help me plz I will give brainliest

Mathematics
1 answer:
Zarrin [17]3 years ago
6 0

Answer:

Step-by-step explanation:

(35 - 20)/20

15/20 = .75

.75 * 100 == 75%

75%

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one angle of a triangle measures 120 degrees. the other two angles are congruent. write and solve an equation to find the measur
Bogdan [553]
The three angles of a triangle always add to 180, do the 2 congruent angles must measure 180-120=60. this number must be divided in two since the angles are congruent, so 60/2=30. [email protected], as needed. so the equation to find x, the size of the congruent angles, would be

x=(180-120)/2
3 0
3 years ago
Is the product of 18 negative numbers and 20 positive numbers a positive number or negative
anastassius [24]

Answer:

positive

Step-by-step explanation:

even negatives = positive

whatever positives = positive

positive*positive = positive

4 0
3 years ago
BRAINLIEST AND 30 POINTS FOR WHOEVER CAN EXPLAIN HOW TO GET THESE ANSWERS...
Dvinal [7]

Step-by-step explanation:

  • Since m∠ACM = 90°, then by angle addition, m∠ACP + m∠PCM = 90°.
  • Since CP⊥ AM, then by definition of perpendicular, m∠APC = 90°.  Since angles of a triangle add up to 180°, that means m∠PAC + m∠ACP = 90°.
  • By substitution, m∠PCM = m∠PAC.
  • Since m∠PCM + m∠CMP = 90°, then by substitution, m∠CMP = m∠PAC.
  • Therefore, by AAA, △ACP and △CMP are similar.

Having proven that the triangles are similar, we can write the proportion:

AP / CP = CP / MP

9 / CP = CP / 16

CP² = 144

CP = 12

Now, we can simply use Pythagorean theorem to find the other sides.

AC² = AP² + CP²

AC² = 9² + 12²

AC = 15

CM² = CP² + PM²

CM² = 12² + 16²

CM = 20

8 0
3 years ago
Find the midpoint of a segment with endpoints A(-3,10) and B(9,2).
lilavasa [31]

Answer:

(3, 6)

Step-by-step explanation:

You add the x points together and divide by two, then you add the y points together and divide by 2.

3 0
3 years ago
Read 2 more answers
Using the Breadth-First Search Algorithm, determine the minimum number of edges that it would require to reach
jekas [21]

Answer:

The algorithm is given below.

#include <iostream>

#include <vector>

#include <utility>

#include <algorithm>

using namespace std;

const int MAX = 1e4 + 5;

int id[MAX], nodes, edges;

pair <long long, pair<int, int> > p[MAX];

void initialize()

{

   for(int i = 0;i < MAX;++i)

       id[i] = i;

}

int root(int x)

{

   while(id[x] != x)

   {

       id[x] = id[id[x]];

       x = id[x];

   }

   return x;

}

void union1(int x, int y)

{

   int p = root(x);

   int q = root(y);

   id[p] = id[q];

}

long long kruskal(pair<long long, pair<int, int> > p[])

{

   int x, y;

   long long cost, minimumCost = 0;

   for(int i = 0;i < edges;++i)

   {

       // Selecting edges one by one in increasing order from the beginning

       x = p[i].second.first;

       y = p[i].second.second;

       cost = p[i].first;

       // Check if the selected edge is creating a cycle or not

       if(root(x) != root(y))

       {

           minimumCost += cost;

           union1(x, y);

       }    

   }

   return minimumCost;

}

int main()

{

   int x, y;

   long long weight, cost, minimumCost;

   initialize();

   cin >> nodes >> edges;

   for(int i = 0;i < edges;++i)

   {

       cin >> x >> y >> weight;

       p[i] = make_pair(weight, make_pair(x, y));

   }

   // Sort the edges in the ascending order

   sort(p, p + edges);

   minimumCost = kruskal(p);

   cout << minimumCost << endl;

   return 0;

}

8 0
3 years ago
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