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Jlenok [28]
3 years ago
10

Mega question with brainliest

Mathematics
2 answers:
pickupchik [31]3 years ago
8 0

Answer:

c:-$12

Step-by-step explanation:

34+30=64.

then 64 - 76=-12

bogdanovich [222]3 years ago
4 0

Answer:

-12

Step-by-step explanation:

You start off with $34 so +34

Then you spend $76 so -76

Then you deposit $30 so +30

There are several ways to go about this but i find the easiest way is to add the positives first.

We're going to say 34+30=64

Next we subtract 76 from 64= -12

You go about this in the same way you would if it didn't have a negative sign in front of it. Then since the 76 is the larger number you add the negative sign.  

  -76

-   64

-----------

  -12

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Use sigma notation to represent the sum of the first seven terms of the following sequence -4,-6,-8.....
lina2011 [118]

Answer:Answer:

\sum\left {{7} \atop {1}} \right -n(3+n)

Step-by-step explanation:

Given the sequence -4,-6,-8..., in order to get sigma notation to represent the sum of the first seven terms of the sequence, we need to first calculate the sum of the first seven terms of the sequence as shown;

The sum of an arithmetic series is expressed as S_n = \frac{n}{2}[2a+(n-1)d]

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Required

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S_7 = \frac{7}{2}[2(-4)+(7-1)(-2)]\\\\S_7 =  \frac{7}{2}[-8+(6)(-2)]\\\\S_7 =  \frac{7}{2}[-8-12]\\\\\\S_7 = \frac{7}{2} * -20\\\\S_7 = -70

The sum of the nth term of the sequence will be;

S_n = \frac{n}{2}[2(-4)+(n-1)(-2)]\\\\S_n = \frac{n}{2}[-8+(-2n+2)]\\\\S_n = \frac{n}{2}[-6-2n]\\\\S_n =  \frac{-6n}{2} -  \frac{2n^2}{2}\\S_n = -3n-n^2\\\\S_n = -n(3+n)

The sigma notation will be expressed as \sum\left {{7} \atop {1}} \right -n(3+n). <em>The limit ranges from 1 to 7 since we are to  find  the sum of the first seven terms of the series.</em>

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