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oee [108]
3 years ago
14

Is this a linear function? One person sends an email to 2 people. Those 2 people send it to 4 people, and those 4 send it to 8 p

eople.
Mathematics
1 answer:
Mumz [18]3 years ago
8 0
Yes; this is a linear function because you plug in a number and multiply it by two, so the function would be y=2x, which is linear despite the fact that it lacks a b value.

Hope this helps! :)
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Help please thanks in advance
DochEvi [55]
What does the black say, the options
3 0
2 years ago
WILL NAME BRAINLIST PLEASE
algol13

Answer:

x = -4y

<em>Hope that helps! :)</em>

<em>-Aphrodite</em>

Step-by-step explanation:

3 0
3 years ago
A boat is heading towards a lighthouse, whose beacon-light is 136 feet above the
alexandr1967 [171]

The distance between the points A to B is 899.9 feet. After rounding off the  nearest integer we get 900 feet as the final answer.

Given we know that CD is perpendicular to AD.

The distance between CD is 139 feet.

As from points A the boat's crew measure the angle of elevation to the beacon as 6°

therefore, m∠A = 6°

Another time the angle of elevation is measured from point B which is 19°.

therefore, m∠DBC = 19°

tan 19° = CD/BD

BD = CD/tan19°

BD = 136/tan 19°

now for tan 6° = CD/AD (tangent is opposite over adjacent)

AD = CD/tan 6°

AD = 136/tan 6°

AB = AD ₋ BD

AB = 136/tan 6° ₋ 136/tan 19°

AB = 1295.2 ₋ 395.3

AB = 900 feet

hence the distance from point A to B is 900 feet.

Learn more about Heights and distances here:

brainly.com/question/2004882

#SPJ9

5 0
1 year ago
L || m
Alona [7]

Answer:

c. m∠1 + m∠6 = m∠4 + m∠6

Step-by-step explanation:

Given: The lines l and m are parallel lines.

The parallel lines cut two transverse lines. Here we can use the properties of transverse and find the incorrect statements.

a.  m∠1 + m∠2 = m∠3 + m∠4

Here m∠1 and m∠2 are supplementary angles add upto 180 degrees.

m∠3 and  m∠4 are supplementary angles add upto 180 degrees.

Therefore, the statement is true.

b. m∠1 + m∠5 = m∠3 + m∠4

m∠1 + m∠5 = 180 same side of the adjacent angles.

m∠3 + m∠4 = 180, supplementary angles add upto 180 degrees.

Therefore, the statement is true.

Now let's check c.

m∠1 + m∠6 = m∠4 + m∠6

We can cancel out m∠6, we get

m∠1 = m∠4 which  is not true

Now let's check d.

m∠3 + m∠4 = m∠7 + m∠4

We can cancel out m∠4, we get

m∠3 = m∠7, alternative interior angles are equal.

It is true.

Therefore, answer is c. m∠1 + m∠6 = m∠4 + m∠6

3 0
3 years ago
In a process that manufactures bearings, 90% of the bearings meet a thickness specification. A shipment contains 500 bearings. A
vredina [299]

Answer:

c) P(270≤x≤280)=0.572

d) P(x=280)=0.091

Step-by-step explanation:

The population of bearings have a proportion p=0.90 of satisfactory thickness.

The shipments will be treated as random samples, of size n=500, taken out of the population of bearings.

As the sample size is big, we will model the amount of satisfactory bearings per shipment as a normally distributed variable (if the sample was small, a binomial distirbution would be more precise and appropiate).

The mean of this distribution will be:

\mu_s=np=500*0.90=450

The standard deviation will be:

\sigma_s=\sqrt{np(1-p)}=\sqrt{500*0.90*0.10}=\sqrt{45}=6.7

We can calculate the probability that a shipment is acceptable (at least 440 bearings meet the specification) calculating the z-score for X=440 and then the probability of this z-score:

z=(x-\mu_s)/\sigma_s=(440-450)/6.7=-10/6.7=-1.49\\\\P(z>-1.49)=0.932

Now, we have to create a new sampling distribution for the shipments. The size is n=300 and p=0.932.

The mean of this sampling distribution is:

\mu=np=300*0.932=279.6

The standard deviation will be:

\sigma=\sqrt{np(1-p)}=\sqrt{300*0.932*0.068}=\sqrt{19}=4.36

c) The probability that between 270 and 280 out of 300 shipments are acceptable can be calculated with the z-score and using the continuity factor, as this is modeled as a continuos variable:

P(270\leq x\leq280)=P(269.5

d) The probability that 280 out of 300 shipments are acceptable can be calculated using again the continuity factor correction:

P(X=280)=P(279.5

8 0
3 years ago
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