Answer:
0.024
Step-by-step explanation:
Sample size (n) = 146 people
The proportion (p) of people who answered that they would be interested in seeing the show again is:

The standard error for a sample of size 'n' and proportion 'p' is:

The standard error for the sample proportion of audience members who want to see the show again is 0.024.
Step-by-step explanation:
That is my answer, luckily I did the test
Answer:
1.7689 (rounded to 4 decimal places)
Step-by-step explanation:
Let the number we are seeking be "x", thus we can write the equation as:

Since we have raised "x" to the "10th power", to get "x" back again, we need to take 10th root. Same goes for right side, we take 10th root of 300. We will get our answer. The process shown below:
![x^{10}=300\\\sqrt[10]{x^{10}} =\sqrt[10]{300} \\x=\sqrt[10]{300} \\x=1.7689](https://tex.z-dn.net/?f=x%5E%7B10%7D%3D300%5C%5C%5Csqrt%5B10%5D%7Bx%5E%7B10%7D%7D%20%3D%5Csqrt%5B10%5D%7B300%7D%20%5C%5Cx%3D%5Csqrt%5B10%5D%7B300%7D%20%5C%5Cx%3D1.7689)
hence, 1.7689 raised to 10th power will give us 300
1/2.
divide everything by 9.
*see attachment showing the line graph
Answer:
2
Step-by-step explanation:
The red line represents the line for women, while the blue line represents the line for men.
Age 45 is the middle of 40 and 45 on the x-axis.
The average number of awakenings during the night for 45 -year-old men ≈ 5
The average number of awakenings during the night for 45 -year-old women = 3
The difference = 5 - 3 = 2 times during the night.