2 years ago

PLEASE HELP! I AM VERY CONFUSED

Mathematics

1 answer:

DerKrebs [107]2 years ago

3 0

Answer: I am the saving grace

Step-by-step explanation:

In the attachments :)

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__<br> What is √68 in simplest radical form?

natka813 [3]

The simplest radical form is $2 \sqrt{17}$

Explanation:

The expression is $\sqrt{68}$

To determine the radical form, let us write the number 68 as a product of prime factors.

Thus, we have,

$\sqrt{68} =\sqrt{2\times2\times17}$

Since, 2, 17 are prime factors and hence, no further factorization is possible.

Hence, it can be written as,

$\sqrt{68} =\sqrt{2^{2} \times17}$

Applying the radical rule $\sqrt{a b}=\sqrt{a} \ \sqrt{b}$ , we have,

$\sqrt{68} =\sqrt{2^{2}} \sqrt{17}$

Simplifying, we have,

$\sqrt{68} =2 \sqrt{17}$

Thus, the simplest radical form is $2 \sqrt{17}$

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3 years ago

A) Write 6.04 x 10 as an ordinary number

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b)2.4×10^6

c)1.47×10^-3

Step-by-step explanation:

here is the answer

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