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nlexa [21]
3 years ago
7

Find the GCF of the terms of the polynomial.

Mathematics
1 answer:
-BARSIC- [3]3 years ago
4 0
<h3>Answer:   2z^3</h3>

====================================================

Explanation:

The GCF of the coefficients {6, -42, 14} is 2 as it is the largest factor found in each of the three values.

----------

For the variable portions, we can

  • write z^5 as z^3*z^2
  • write z^4 as z^3*z^1
  • write z^3 as z^3*1

Each time we see z^3 show up, so this is the largest common factor among the three variable terms.

----------

The two results we got were 2 and z^3

Putting the two results together, we end up with the overall GCF of 2z^3

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12 + 18 = 30 total apples
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5 0
3 years ago
It is estimated that 0.54 percent of the callers to the Customer Service department of Dell Inc. will receive a busy signal. Wha
stira [4]

Using the binomial distribution, it is found that there is a 0.8295 = 82.95% probability that at least 5 received a busy signal.

<h3>What is the binomial distribution formula?</h3>

The formula is:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • 0.54% of the calls receive a busy signal, hence  p = 0.0054.
  • A sample of 1300 callers is taken, hence n = 1300.

The probability that at least 5 received a busy signal is given by:

P(X \geq 5) = 1 - P(X < 5)

In which:

P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4).

Then:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{1300,0}.(0.0054)^{0}.(0.9946)^{1300} = 0.0009

P(X = 1) = C_{1300,1}.(0.0054)^{1}.(0.9946)^{1299} = 0.0062

P(X = 2) = C_{1300,2}.(0.0054)^{2}.(0.9946)^{1298} = 0.0218

P(X = 3) = C_{1300,3}.(0.0054)^{3}.(0.9946)^{1297} = 0.0513

P(X = 4) = C_{1300,4}.(0.0054)^{4}.(0.9946)^{1296} = 0.0903

Then:

P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.0009 + 0.0062 + 0.0218 + 0.0513 + 0.0903 = 0.1705.

P(X \geq 5) = 1 - P(X < 5) = 1 - 0.1705 = 0.8295

0.8295 = 82.95% probability that at least 5 received a busy signal.

More can be learned about the binomial distribution at brainly.com/question/24863377

#SPJ1

6 0
1 year ago
Simplify the function
dusya [7]

Answer:

Step-by-step explanation:

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2 years ago
How can you 24 with the numbers 6,6,2,1
Andreas93 [3]

Add 6 + 6 = 12

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5 0
2 years ago
Please anyone help me answer this question am giving the brainliest
DochEvi [55]

Answer:

(-3/2x+1) + (3/x-1)

Step-by-step explanation:

Dont put the answer in parenthesis, I just did that to seprate it so it was easier to read. If you need it to be put in word form for it to be easier for you to understand, its "negative three divided by two x plus one, plus 3 divided by x minus 1"

First, rewrite the expression as 3x+6/2x^2+x-2x-1

Then, factor the expression, 3x+6/x*(2x+1)-(2x+1) (*=multiply)

Then, write a new fraction for each factor in the denominator, then write a new fraction, 3x+6/(2x+1)*(x-1) to (A)/2x+1 + B/x-1)

Then write terms in the numerators, for now we will use A and B.

Now we set the sum of the fractions equal to the original fraction.

3x+6/(2x+1)*(x-1) = A)/2x+1 + B/x-1).

Then reorder and group the terms, giving you 3x+6=(A+2B)x+(-A+B).

Now equate the coefficiants, {6= -A+B, 3= A+2B

Then substitute back, (A, B)=(-3, 3)

Now finally, just rewrite the fraction. (-3/2x+1) + (3/x-1)

Hope this helps! Sorry its kind of long.

6 0
2 years ago
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