In the right triangle shown m
1 answer:
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Answer:
Kite
Step-by-step explanation:
To graph quadrilateral with points:
A(-1,-2)
B(5,1)
C(-3,1)
D(-1,4)
Thus, we graph the the given points and join the corners. The quadrilateral formed has the following features:
Measure of segment AB= Measure of segment BD = 6.708 units
Measure of segment AC= Measure of segment CD = 3.605 units
Thus, adjacent pair of sides of the quadrilateral are congruent.
Major diagonal BC cuts the minor diagonal AD at point E such that:
Measure of segment AE= Measure of segment ED = 3 units
m∠AEB = m∠DEB = 90°
Thus, major diagonal is a perpendicular bisector of the minor diagonal.
The above stated features fulfills the criterion of a kite.
Hence, the given quadrilateral ABCD is a kite.
Answer:
I) |xz| ≈ 28.6 km
II) |yz| ≈ 34.8 km
Step-by-step explanation:
Let's assume that the position of ship due south of x is z (aà pictor representation of the question is attached)
|xy| = 20 km, |xz| = ?, |yz| = ?, θ(y) = 55°
Using Trigonometric ratio - SOHCAHTOA
I) Tan θ = |xz| ÷ |xy| ⇒ Tan 55° = |xz| ÷ 20
|xz| = 20 * Tan 55 = 20 * 1.428
|xz| = 28.56 km
|xz| ≈ <u>28.6 km</u>
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II) Cos θ = |xy| ÷ |yz| ⇒ Cos 55° = 20 ÷ |yz|
|yz| * Cos 55° = 20 ⇒ |yz| = 20 ÷ Cos 55°
|yz| = 20 ÷ 0.574 = 34.84 km
|yz| ≈ <u>34.8 km</u>
See attached picture for the answer:
you don't say how to round the answer so I did not round it.
you don't say how to round the answer so I did not round it.