1. 567
2. 33
3. 85%; $17
4. they have 4 pages left
5. (-5,2)
Answer:
Hopes it helps
Step-by-step explanation:
The Quadratic Polynomial is
2 x² +x -4=0
Using the Determinant method to find the roots of this equation
For, the Quadratic equation , ax²+ b x+c=0
(b) x²+x=0
x × (x+1)=0
x=0 ∧ x+1=0
x=0 ∧ x= -1
You can look the problem in other way
the two Quadratic polynomials are
2 x²+x-4=0, ∧ x²+x=0
x²= -x
So, 2 x²+x-4=0,
→ -2 x+x-4=0
→ -x -4=0
→x= -4
∨
x² +x² +x-4=0
x²+0-4=0→→x²+x=0
→x²=4
x=√4
x=2 ∧ x=-2
As, you will put these values into the equation, you will find that these values does not satisfy both the equations.
So, there is no solution.
You can solve these two equation graphically also.
Coplanar lines are R, U, and V
<u>Given </u><u>:</u><u>-</u>
<u>To </u><u>Find</u><u> </u><u>:</u><u>-</u>
- The equation in slope intercept form .
<u>Answer</u><u> </u><u>:</u><u>-</u>
From the given graph , we can see that the line passes through y axis at (0,5) . So the y intercept is 5 . And the slope of the line is 5/2 = 2.5 . So ,
y intercept = 5 .
slope = 5/2 .
Now here we can use the slope intercept form as ,
y = mx + c
y = 5/2x + 5
<u>Hence</u><u> the</u><u> required</u><u> answer</u><u> is</u><u> </u><u>y </u><u>=</u><u> </u><u>5</u><u>/</u><u>2</u><u>x</u><u> </u><u>+</u><u> </u><u>5</u><u>.</u>
Miles? I'm not sure that it'd be km (unless its not an american airline)