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Oduvanchick [21]
4 years ago
8

HELP PLSSSSS AAAAAAAAAAAAAAAAAAAAAA ILL GIVE BRAINLIEST B(

Mathematics
1 answer:
CaHeK987 [17]4 years ago
3 0

Answer:

a(n) = (3/5)a(n-1), where a(1) = 10 and n is 2 or greater.

Step-by-step explanation:

determine the common factor...The first term (10) by 3/5 results in the given second term (6); the third term is 3/5 of the second term (6), resulting in 18/5 (equivalent to 36/10 or 3.6/1, or just 3.6. Resulting in a(n) = (3/5)a(n-1).

the third term is 3.6, which, if mult. by (3/5), produces 2.16, as expected.

Thus, the recursive formula for this geometric sequence is a(n) = (3/5)a(n-1).

This is good only for a(1) = 10 and n = 2, 3, ....

Hope this helps you

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Can someone please explain the second part? I will give brainliest! :)
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You have to find out what the similarity ration is meaning you need to find the scale factor . you simplify create a ratio of the lengths of two corresponding sides of the two polygons . if the ration is the same for all corresponding sides then that’s the scale factor . Anyways the polygons are similar.
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3 years ago
Three consecutive odd intergers have a sum of 27. find the integers
Misha Larkins [42]
Solve for x:
x + (x + 2) + (x + 4) = 27
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3x / 3 = 21 / 3
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3 years ago
Mr. Capuano, an art teacher, surveyed his students to find out whether they are satisfied with his classes. He also noted which
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How do you factor trinomials step by step
bagirrra123 [75]

Answer:

Step 1: Identify the values for b and c. In this example, b=6 and c=8.

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3 years ago
exam p A drawer contains four pairs of socks, with each pair a different color. One sock at a time is randomly drawn from the dr
Marta_Voda [28]

Answer:

The probability that the maximum number of draws is required is 0.2286

Step-by-step explanation:

The probability that the maximum number of draws happens when you pick <em>different colors in the first four pick</em>.

Assume you picked one sock in the first draw. Its probability is 1, since you can draw any sock.

In the second draw, 7 socks left and you can draw all but the one which is the pair of the first draw. Then the probability is \frac{6}{7}

In the third draw, 6 socks left and you can draw one of the two pair colors which are not drawn yet. Its probability is \frac{4}{6}

In the forth draw, 5 socks left and only one pair color, which is not drawn. The probability of drawing one of this pair is \frac{2}{5}

In the fifth draw, whatever you draw, you would have one matching pair.

The probability combined is 1×\frac{6}{7} ×\frac{4}{6}× \frac{2}{5} ≈ 0.2286

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3 years ago
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