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Gre4nikov [31]
3 years ago
9

K/(-11)=-3. Solving one step equations

Mathematics
1 answer:
notka56 [123]3 years ago
6 0
K=33 because it just is. You know because 33 divided by negetive 11 is -3
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A piece of machinery depreciated depriciates 6000 the first year, 5700 the second year and 5400 the third year. If the rate of d
Harrizon [31]

Answer:

The amount of depreciation of piece of machine after 6 years is 4,410 unit  .

Step-by-step explanation:

Given as :

The first year depreciation amount = 6000

The second year depreciation amount = 5700

The third year depreciation amount = 5400

let the rate of depreciation = R

I.e R = \dfrac{\textrm initial value - \textrm afinal value}{\textrm initial value} × 100

or, R = \frac{6000-5700}{5000}  × 100

Or R = \frac{300}{5000}  × 100

So , R = 5 %

This rate of depreciation is constant

Time period = 6 years

Now,

Value of machine after n years = initial value × (1-\dfrac{\textrm rate}{100})^{n}

or, Value of machine after 6 years = 6000 × (1-\dfrac{\textrm 5}{100})^{6}

Or, Value of machine after 6 years = 6000 × (0.95)^{6}

∴ Value of machine after 6 years = 6000 × 0.7350

I.e Value of machine after 6 years = 4,410

Hence The amount of depreciation of piece of machine after 6 years is 4,410 unit  . Answer

3 0
3 years ago
What is a coplanar. You will earn good point.
evablogger [386]
Think about the prefix co-

cooperation
cosign
co-president

It's typically used to describe things that are <em>shared</em> or <em>mutual</em>. We say that two points are <em>coplanar</em> when they <em>share the same plane.</em>
4 0
3 years ago
18 ÷ 9 + 26 × 2 + 3 pemdas
Orlov [11]
So, PEMDAS states that the order should be:
P-Parentheses
E-Exponents
M-Multiplication
D-Division
A-Addition
S-Subtraction

So, we can start by doing the division and multiplication
18/9=2 and 26*2=52
So now, the equation is:
2+52+3
Now just add all of these together, and you get 57

Hope this helped!!!! :D
7 0
3 years ago
Read 2 more answers
Whoever the first to complete this get 5$ and brainlist Leave cashapp or paypal below
valentina_108 [34]

Answer:

17-4*3+18=23

(60-20)÷4+(3*5)=25

3*2+6/4+2(18-3)=33

3*4+4*5=32

15-2*4-(6-3)=4

25+10-5/5=34

a. 72

b. 120

5m-n+p=10 or 5*4-4*3+2=10

Step-by-step explanation:

Okay I officially finished this now Imma go watch tiktoks bye.

6 0
4 years ago
A car can travel 156 kilometers on 13 liters of gasoline. How much gasoline will it need to go 480 kilometers?
vodka [1.7K]

Answer:

40

Step-by-step explanation:

To find how much gasoline is needed for 480 kilometers, we will need to find how much is needed per kilometers:

13 liters is used for 156 kilometers

156/13 = 12 so 1 liter gasoline is spent per 12 kilometers

So for 480 kilometers we would need 40 liter gasoline because

480/12 = 40

8 0
2 years ago
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