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Gre4nikov [31]
3 years ago
9

K/(-11)=-3. Solving one step equations

Mathematics
1 answer:
notka56 [123]3 years ago
6 0
K=33 because it just is. You know because 33 divided by negetive 11 is -3
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Exercise 3 Iron Man is checking out a new suit that fires lasers more accurately. If he is aiming for a bullseye, his original s
Novosadov [1.4K]

Answer: (a). insufficient evidence.

(b). sufficient evidence

(c). insufficient evidence

Step-by-step explanation:

we will analyse this carefully to help us understand it better.

we have the standard deviation for the original suit = 2mm

standard deviation for new suit = 1.6mm

given n = 1.6

from the question we know that  the  suit with less standard deviation is better than the other suit

considering a null hypothesis;

H₀ : б ≥ 2, (here the new suit is not better than the original alternative hypothesis).

Also Hi : б < 2 (we have here that the new suit is better than the original )

using the Chi-Square distribution with n-1 degree of freedom to test the claim about the value of the standard deviation;

X² = (n-1) s²/ б² = (16-1)(1.6)² / (2)² = 9.6

taking the P value of X² (9.6) for 15 D O F  from the P value table gives us

1-0.8441 = 0.1559

also ∝ = 0.05

where P-value > ∝ (0.05)

we can see from here that there is insufficient evidence to claim that new suit is better than that of the original suit, having failed to neglect H₀

(b). Given n = 100 and s = 1.6

then we have that X² = (n-1) s²/ б² = (100-1)(1.6)² / (2)² = 63.36

P-value of X² at 99 dif gives 0.0020

where ∝ = 0.05

since P value < ∝

rejecting the null hypothesis H₀,

we can safely say that there is sufficient claim that the new suit is better than the original at 95%.

(c). where we have that ∝ = 0.001

for part(b) P-values = 0.0020

given P-value > ∝ ;

we fail to neglect the null hypothesis.

From this we can say that the is insufficient evidence backing the claim thhat the new suit is better than the original suit at 99.99% confidence level.

cheers i hope this helps!!!!!

5 0
4 years ago
Simplify each expression: <br> a)4a-3+5a<br> b)t-3t+2t+4<br> c) 3(g+5)+2g<br> d)2t+4)3+6(-5t)-(-8)
Vlad1618 [11]

Answer:

there you go it's all the paper

8 0
3 years ago
two numbered 1 to 6 dice are thrown together and their scores are added. the probability that the sum will be 4 is?​
natulia [17]

Answer:

Pr = \frac{3}{36}

Step-by-step explanation:

Given

2 number die

Required

P(Sum = 4)

The sample space of 2 die is:

S = \{(1, 1) (1, 2) (1, 3) (1, 4) (1, 5) (1, 6), (2, 1) (2, 2) (2, 3) (2, 4) (2, 5) (2, 6)

(3, 1) (3, 2) (3, 3) (3, 4) (3, 5) (3, 6), (4, 1) (4, 2) (4, 3) (4, 4) (4, 5) (4, 6)

(5, 1) (5, 2) (5, 3) (5, 4) (5, 5) (5, 6), (6, 1) (6, 2) (6, 3) (6, 4) (6, 5) (6, 6)

n(S)= 36

The pairs that adds up to 4 are:

Sum(4) = \{(1,3), (2,2),(3,1)\}

n(Sum)  =3

So, the probability is:

Pr = \frac{n(Sum)}{n(S)}

Pr = \frac{3}{36}

5 0
3 years ago
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Debora [2.8K]

Answer:

V=235.62

Step-by-step explanation:

U~U

7 0
3 years ago
Please help, if I get this wrong, my grade will plummet :( /srs
nata0808 [166]
The correct answer is 12
4 0
2 years ago
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