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3 years ago

One more than the product of 19 and a number

Mathematics

1 answer:

djverab [1.8K]3 years ago

5 0

Hello,

Let's assume n the number:

1+19*n

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Which statement about the scenario represented in the table is true? Assume time is the independent variable

Verizon [17]

Answer:B

Step-by-step explanation:

5 0

3 years ago

At Information and Communications University: 31 female seniors were on the dean’s list 62 women were on the dean’s list who wer

inessss [21]

Step-by-step explanation:

There's a lot of information here, so first things first, let's get organized.

Let's start by assigning variable names to each group. We want the variables to be short but easy to understand.

For example, let's say the number of female seniors on the dean's list is FSD (F for female, S for senior, and D for dean's list).

FSD = 31

Sticking to this naming scheme:

FD = 62

MSD = 45

FS = 87

MS = 96

F = 275

MD = 88

M = 227

Now we can begin.

a) We want to know how many seniors there are. So all we have to do is add up all the variables with an S in them.

FSD + MSD + FS + MS

31 + 45 + 87 + 96

259

b) We want to know how many women there are. So add up all the variables with an F in them.

FSD + FD + FS + F

31 + 62 + 87 + 275

455

c) We want to know how many are on the dean's list. So add up all the variables with a D in them.

FSD + FD + MSD + MD

31 + 62 + 45 + 88

226

d) Now we want to know how many are seniors AND on the dean's list. So add up all the variables that have both an S and a D.

FSD + MSD

31 + 45

e) We want to know how many female seniors there are, so add up all the variables with both an F and an S.

FSD + FS

31 + 87

118

f) We want to know how many women were on the dean's list, so add up all the variables with both an F and a D.

FSD + FD

31 + 62

g) Finally, we want to know how many students there are total. So add up all the variables.

FSD + FD + MSD + FS + MS + F + MD + M

62 + 45 + 87 + 96 + 275 + 88 + 227

880

5 0

3 years ago

Eduardo and Sarawong are selling wrapping paper for a school fundraiser. Eduardo sold 5 rolls of plain wrapping paper and 5 roll

Digiron [165]

Answer: A roll of plain wrapping paper costs $17, while a roll of holiday wrapping paper costs $20.

Step-by-step explanation: First let us represent a roll of plain wrapping paper with letter p and a roll of holiday wrapping paper would be represented by d. If Eduardo sold 5 rolls of plain wrapping paper and 5 rolls of holiday wrapping paper for $185, then we can express this as

5p+ 5d= 185

Also if Sarawong sold 14 rolls of plain wrapping paper and 5 rolls of holiday wrapping paper for $338, then this too can be expressed as

14p + 5d = 338

Now we have a pair of simultaneous equations which are,

5p + 5d = 185 ———(1)

14p + 5d = 338 ———(2)

Since all the variables have coefficients greater than 1, we shall use the elimination method. Note that the coefficients of the d variable are both 5, so straight away we subtract equation (1) from equation (2) and we now have;

(14p - 5p) + (5d - 5d) = 338 - 185

9p = 153

Divide both sides of the equation by 9

p = 17

Having calculated p, we can now substitute for the value of p into equation (1)

5p + 5d = 185

5(17) + 5d = 185

85 + 5d = 185

Subtract 85 from both sides of the equation

5d = 100

Divide both sides of the equation by 5

d = 20

Hence, the cost per roll of plain wrapping paper is $17, while the cost per roll of holiday wrapping paper is $20.

5 0

3 years ago

QUESTION OF THE DAY: There are 5 blue M&Ms, 6 red M&Ms, 5 yellow M&Ms, 8 green M&Ms, 4 orange M&Ms, and 7 br

Nadya [2.5K]

Answer:

15/35

Step-by-step explanation:

7 0

3 years ago

PLEASE HELP ASAP I REALLY NEED HELP AND EXPLINATION I WILL GIVE BRAINLIEST!!

Lady bird [3.3K]

The given data can be completed in a tabular form by using the given data

points row and column totals.

Responses:

Part A: The percentage of the respondents that do not like both hamburgers and burritos is approximately 26.34%

Part B: The marginal relative frequency is approximately 0.537

Part C: The data point that has strongest association of its two factors is the data point for the respondents that like hamburger but do not like burritos which is 81

<h3>Methods used for the calculations:</h3>

The given data is presented as follows;

$\begin{tabular}{|l|c|c|c|}&Like hamburgers&Does not like hamburgers& Total\\Likes burritos&29&41&\\Does not like burritos &&54&135\\Total&110&&205\end{array}\right]$

Number of respondents that do not like burritos = 135 - 54 = 81

The total number of respondents that do not like hamburgers = 41 + 54 = 95

The total number of respondents that like burritos = 29 + 41 = 70

Part A:

Number of respondents that do not like both hamburgers and burritos = 54

The percentage of the survey that do not like both hamburgers and burritos (H∩B)' is therefore;

$Percentage \ of \ (H \cap B)' = \mathbf{\dfrac{54}{205} \times 100} = 26.\overline{34146} \ \% \approx 26.34 \ \%$

The percentage that do not like both hamburgers and burritos is approximately <u>26.34%</u>

Part B:

Marginal relative frequency of all customers that like hamburgers.

$Marginal \ relative \ frequency = \mathbf{\dfrac{Total \ number \ of \ customers \ that \ like \ hamburgers}{Grand \ total \ of \ repondents \ in \ the \ survey}}$

Therefore;

$Marginal \ relative \ frequency = \dfrac{110}{205} = \dfrac{22}{41} \approx \underline{ 0.537}$

Part C:

The completed table is presented as follows;

$\begin{tabular}{|l|c|c|c|}&Like hamburgers&Does not like hamburgers&Total\\Likes burritos&29&41&70\\Does not like burritos&81&54&135\\Total&110&95& 205\end{array}\right]$

The conditional relative frequencies are presented as follows;

$Conditional \ relative \ frequency \ (row)\\\begin{tabular}{|l|c|c|c|}& Cond. Rel. Frequency&&Total\\Likes burritos&29 \div 70 \approx 0.414&41 \div 70 \approx 0.586 &70 \div 70 = 1 \\Does not like burritos&81 \div 135 = 0.6&54 \div 135= 0.4&135 \div 135 = 1\end{array}\right]$

$Conditional\ Relative \ Frequencies \ (column)\\\begin{tabular}{|l|c|c|c|}&Like hamburgers&Does not like hamburgers\\Likes burritos&29 \div 110 \approx 0.263&41 \div 95 \approx 0.432\\Does not like burritos&81 \div 110 \approx 0.763&54 \div 95 \approx 0.568 \\&110 \div 110 = 1&95 \div 95 = 1\end{array}\right]$

A strong association variables relates to how much a variable depends on another variable, which is the level of relationship.

Based on the above relative frequency tables, we have that the data point

for those that like hamburger (29, 81) is such that only approximately 26.3%

of those that like hamburgers like burritos, while 76.3% that like hamburger

do not like burritos, which can be interpreted as follows;

Majority of customers that like hamburgers (76.3%) do not like burritos

Therefore;

A data point that has the strongest association is the data point for the customers that like hamburgers and do not like burritos which is <u>81</u>.

Learn more conditional relative frequency table

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3 0

2 years ago