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OlgaM077 [116]
2 years ago
14

The sun produces 3.9 x 10^33 ergs of radiant energy per second. how many ergs of radiant energy does the sun produce in 3.25 x 1

0^3 seconds?
Mathematics
2 answers:
Alex_Xolod [135]2 years ago
6 0
(3.9 x 10^33) * (3.25 x 10^3) = 
(3.9 x 3.25) * (10^33 * 10^3) =
12.675 x 10^36 <==
taurus [48]2 years ago
4 0

Answer:

1.2675 x 10^37

Step-by-step explanation:

you would have to first multiply 3.9 x 3.25 =12.675. It is not in scientific notation so you would have to change the decimal 1.2675 x 10^37

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6. Use the Rational Root (Zero) Theorem to list all the possible real roots (zeros).
maks197457 [2]
The left side
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8 0
2 years ago
If g(x)=3x-11, what is x is g(x)=289
Liula [17]

Answer:x=100

Step-by-step explanation:

Since you know that g(x)=3x-11 all you have to do is substitute that into g(x)=289. So you get 3x-11=289. To get x you have to add 11 on both sides.

3x-11=289

+11 +11

----------------

3x = 300

Divide 3 on both sides to get x by itself

3x =300

---- -------

3 3

x=100

8 0
3 years ago
I have a question on a homework problem. Select the function that represents an arithmetic sequence.
Fynjy0 [20]
7 ig because I mean if you take a look at the problem
4 0
2 years ago
Topic: The Quadratic Formula
Finger [1]

Answer:

Step-by-step explanation:

The quadratic formula for a equation of form

ax²+bx + c = 0 is

x= \frac{-b +- \sqrt{b^2-4ac} }{2a}

For the first equation,

x²+3x-4=0,

we can match that up with the form

ax²+bx + c = 0

to get that

ax² =  x²

divide both sides by x²

a=1

3x = bx

divide both sides by x

3 = b

-4 = c

. We can match this up because no constant multiplied by x could equal x² and no constant multiplied by another constant could equal x, so corresponding terms must match up.

Plugging our values into the equation, we get

x= \frac{-3 +- \sqrt{3^2-4(1)(-4)} }{2(1)} \\= \frac{-3+-\sqrt{25} }{2} \\ = \frac{-3+-5}{2} \\= -8/2 or 2/2\\=  -4 or 1

as our possible solutions

Plugging our values back into the equation, x²+3x-4=0, we see that both f(-4) and f(1) are equal to 0. Therefore, this has 2 real solutions.

Next, we have

x²+3x+4=0

Matching coefficients up, we can see that a = 1, b=3, and c=4. The quadratic equation is thus

x= \frac{-3 +- \sqrt{3^2-4(1)(4)} }{2(1)}\\= \frac{-3 +- \sqrt{9-16} }{2}\\= \frac{-3 +- \sqrt{-7} }{2}\\

Because √-7 is not a real number, this has no real solutions. However,

(-3 + √-7)/2 and (-3 - √-7)/2 are both possible complex solutions, so this has two complex solutions

Finally, for

4x² + 1= 4x,

we can start by subtracting 4x from both sides to maintain the desired form, resulting in

4x²-4x+1=0

Then, a=4, b=-4, and c=1, making our equation

x=\frac{-(-4) +- \sqrt{(-4)^2-4(4)(1)} }{2(4)} \\= \frac{4+-\sqrt{16-16} }{8} \\= \frac{4+-0}{8} \\= 1/2

Plugging 1/2 into 4x²+1=4x, this works as the only solution. This equation has one real solution

7 0
2 years ago
How many different 2 digit numbers can you make with 4,6, and 8 if the numbers can not be repeated
Morgarella [4.7K]

Answer:

6

Step-by-step explanation:

46, 48, 64, 68, 86, 84

8 0
2 years ago
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