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mezya [45]
3 years ago
6

"latex-formula">
Mathematics
1 answer:
Triss [41]3 years ago
7 0

Answer:

x = √21, x = -√21

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Find the missing numerator in each of the following fractiions? A. 5/6= /12. B. 2/4= /36. C. 2/5=/20. D. 4/25=/100
zalisa [80]

Answer:

A) The numerator is 10.

B)The numerator is 18.

C)The numerator is 8.

D)The numerator is 16.

Step-by-step explanation:

A) \frac{5}{6}=\frac{x}{12}

\frac{5\times 12}{6}=10

\frac{5}{6}=\frac{10}{12}

The numerator is 10.

B) \frac{2}{4}=\frac{x}{36}

\frac{2\times 36}{4}=18

\frac{2}{4}=\frac{18}{36}

The numerator is 18.

C) \frac{2}{5}=\frac{x}{20}

\frac{2\times 10}{5}=8

\frac{2}{5}=\frac{8}{20}

The numerator is 8.

D)\frac{4}{25}=\frac{x}{100}

\frac{4\times 100}{25}=16

\frac{4}{25}=\frac{16}{100}

The numerator is 16.

4 0
4 years ago
Please help
V125BC [204]

A

B

F

These i think

Hope this helps

3 0
3 years ago
Out of 200 people sampled, 52 had kids. Based on this, construct a 99% confidence interval for the true population proportion of
iragen [17]

Answer:

0.180144 < p < 0.339856

Step-by-step explanation:

According to the Question,

  • Given That, Out of 200 people sampled, 52 had kids, Thus the proportion of the mean is 52/200 = 0.26

⇒ standard error of the sample is square root(0.26 * (1-0.26) / 200) = 0.031

⇒alpha(a) = 1 - 99/100 = 0.01

⇒critical probability(p*) = 1 - a/2 = 0.995

⇒assuming a normal distribution, look for the z-score associated with 0.995 cumulative probability , z-score = 2.576

⇒margin of error(ME) = 2.576 * 0.031 = 0.079856

  • the confidence interval is 0.26 + or - 0.079856

0.180144 < p < 0.339856

3 0
3 years ago
2x + 48 &lt; 8x Solve for X
NeX [460]
<h2>Answer: </h2><h2>x > 8</h2><h2>~</h2><h3>To solve for X, isolate the variable 'x' by dividing each side by factors that don't contain the variable 'x'.</h3><h3>Inequality Form:</h3><h3>x > 8</h3><h3>Interval Notation:</h3><h3>(8,\infty) or (8, ∞)</h3><h2>~</h2>

Hope you have a good day, Loves!

Also if I'm right can you let me know, please?

<em>Also Also if I am right can I please have Brainliest??</em>

<u><em>You don't need to, I'm just glad I could help. ^^</em></u>

5 0
3 years ago
Help please…………………………..
gavmur [86]

Answer: is A i know this because i just took the test.

5 0
3 years ago
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