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Vladimir [108]
3 years ago
13

How do i write 12+(43-7)÷6 in order of operations

Mathematics
2 answers:
Lunna [17]3 years ago
7 0
Bidmas so 43-7 then divide by 6 then add 12
Kitty [74]3 years ago
7 0
Using PEMDAS

P: parenthesis
E: exponents
M: multiplication
D: division
A: addition
S: subtraction

In this case <span>12+(43-7)÷6
you need to do </span>parenthesis first (43-7)
then division, ÷6
then addition, 12+

12+(43-7) ÷ 6
= 12 + 36 ÷ 6
= 12 + 6
= 18
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