I am preety sure it is 10 times greater
Answer:
b
Step-by-step explanation:
Answer:
![f=17\\p=9\\](https://tex.z-dn.net/?f=f%3D17%5C%5Cp%3D9%5C%5C)
Step-by-step explanation:
Let
![f= Full-time\\p=Part-time](https://tex.z-dn.net/?f=f%3D%20Full-time%5C%5Cp%3DPart-time)
Full time rates-$275, Part-time rates-$140
The problem can be expressed as:
![f+p=26...eqtn1\\275f+140p=5935....eqtn2\\](https://tex.z-dn.net/?f=f%2Bp%3D26...eqtn1%5C%5C275f%2B140p%3D5935....eqtn2%5C%5C)
Express eqtn1 in terms of f,![f=26-p](https://tex.z-dn.net/?f=f%3D26-p)
Substitute f value in eqtn 2.
![=>275(26-p)+140p=5935\\7150-275p+140p=5935\\1215=135p\\p=9\\f=26-9=17\\](https://tex.z-dn.net/?f=%3D%3E275%2826-p%29%2B140p%3D5935%5C%5C7150-275p%2B140p%3D5935%5C%5C1215%3D135p%5C%5Cp%3D9%5C%5Cf%3D26-9%3D17%5C%5C)
Therefore, jeds has 17 fulltime and 9 parttime employees.
The answer is 25.
-1/5n = -5
-n = -25
n = 25
5/10+1/10=6/10, they are equivalent since the denominator is the same :)