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3 years ago

Out of 45 students 29 went on field trip. Which best represents the percent of the students who do not go on trip?

1 answer:

4 0

To find the percentage, divide 29 by 45 (29÷45). You should get 0.64444444(so on). Round that to 0.64 and your answer is 64%

You might be interested in

The yoga instructor earns$25 per class and $10 per student that shows up. They want to earn more than $385 teaching 6 classes th

Sedaia [141]

ANSWER: 24 people

All you have to do is multiply 25 and 6 to get 150. Then minus 150 from 385 to get 235. Then divide 235 by 10 to get 23.5, since you can not have half a person the answer is to round up to 24.

3 0

1 year ago

Read 2 more answers

24/10 into hundredths

dalvyx [7]

Answer:

240/100

Step-by-step explanation:

just multiply 24 by 10 to get hundredths

6 0

2 years ago

A common blood test performed on pregnant women to screen for chromosome abnormalities in the fetus measures the human chorionic

goldfiish [28.3K]

Answer:

(a) The proportion of women who are tested, get a negative test result is 0.82.

(b) The proportion of women who get a positive test result are actually carrying a fetus with a chromosome abnormality is 0.20.

Step-by-step explanation:

The Bayes' theorem states that the conditional probability of an event E $_{i}$ , of the sample space S, given that another event A has already occurred is:

$P(E_{i}|A)=\frac{P(A|E_{i})P(E_{i})}{\sum\liits^{n}_{i=1}{P(A|E_{i})P(E_{i})}}$

The law of total probability states that, if events E₁, E₂, E₃... are parts of a sample space then for any event A,

$P(A)=\sum\limits^{n}_{i=1}{P(A|B_{i})P(B_{i})}$

Denote the events as follows:

X = fetus have a chromosome abnormality.

Y = the test is positive

The information provided is:

$P(X)=0.04\\P(Y|X)=0.90\\P(Y^{c}|X^{c})=0.85$

Using the above the probabilities compute the remaining values as follows:

$P(X^{c})=1-P(X)=1-0.04=0.96$

$P(Y^{c}|X)=1-P(Y|X)=1-0.90=0.10$

$P(Y|X^{c})=1-P(Y^{c}|X^{c})=1-0.85=0.15$

(a)

Compute the probability of women who are tested negative as follows:

Use the law of total probability:

$P(Y^{c})=P(Y^{c}|X)P(X)+P(Y^{c}|X^{c})P(X^{c})$

$=(0.10\times 0.04)+(0.85\times 0.96)\\=0.004+0.816\\=0.82$

Thus, the proportion of women who are tested, get a negative test result is 0.82.

(b)

Compute the value of P (X|Y) as follows:

Use the Bayes' theorem:

$P(X|Y)=\frac{P(Y|X)P(X)}{P(Y|X)P(X)+P(Y|X^{c})P(X^{c})}$

$=\frac{(0.90\times 0.04)}{(0.90\times 0.04)+(0.15\times 0.96)}$

$=0.20$

Thus, the proportion of women who get a positive test result are actually carrying a fetus with a chromosome abnormality is 0.20.

6 0

3 years ago

You sell T- shirts for a fundraiser. It cost $112 to have the T- shirts made. You make $98 in sales. What is your profit

faust18 [17]

You make -$14, or you lose $1

8 0

3 years ago

What is 2X to the power of 3 divided by -8X to the power of 4?

PIT_PIT [208]

Answer: 8 = 23 (-8)4 = (23)4 = 212

1/(2048x)

Step-by-step explanation:Negative number raised to an even power is positive

For example let's look at (-7)6 , where (-7) , a negative number, is raised to 6 , an even exponent :

(-7)6 can be written as (-7)•(-7)•(-7)•(-7)•(-7)•(-7)

Now, using the rule that says minus times minus is plus, (-7)6 can be written as (49)•(49)•(49) which in turn can be written as (7)•(7)•(7)•(7)•(7)•(7) or 76 which is positive.

We proved that (-7)6 is equal to (7)6 which is a positive number

Using the same arguments as above, replacing (-7) by any negative number, and replacing the exponent 6 by any even exponent, we proved which had to be proved

Dividing exponential expressions : x3 divided by x4 = x(3 - 4) = x(-1) = 1/x1 = 1/x

Final result :

1/2048x

im in middle school

6 0

2 years ago