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Naya [18.7K]
3 years ago
5

Determine the distance between -3 and 6.

Mathematics
2 answers:
Vika [28.1K]3 years ago
7 0

Answer:

A) -9 units is the distance between -3 and 6

vitfil [10]3 years ago
4 0

Answer:

D)

9 units

Step-by-step explanation:

distance = 6 - ( - 3) = 6 + 3 = 9 \: units

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Determine the radius and center of the circle with the following equation <br> x^2+y^2-12x+24y-10=6
PolarNik [594]

Answer:

Center: (6, -12)

Radius: 4

Step-by-step explanation:

<u>Complete the squares</u>

<u />x^2+y^2-12x+24y-10=6\\\\x^2-12x-10+y^2+24y=6\\\\x^2-12x-10+46+y^2+24y+144=6+46+144\\\\(x^2-12x+36)+(y^2+24y+144)=196\\\\(x-6)^2+(y+12)^2=196

Comparing with the standard form equation (x-h)^2+(y-k)^2=r^2, since r^2=196, then the radius of the circle is r=14. Also, the center of the circle would be (h,k)\rightarrow(6,-12).

8 0
2 years ago
Grant attempted to solve an equation but made an error. What is his error, and
Vlad1618 [11]

Answer:

No Solution.

Step-by-step explanation:

-4+2x=5-(x-3)+3x

-4+2x=5-x+3+3x

-4+2x=5+3-x+3x

-4+2x=8+2x

-4+2x-2x=8

-4+0=8

-4=8

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4 0
3 years ago
Help meeeee!!!
natulia [17]

Answer:

Taylor is closest to the table

Step-by-step explanation:

I divided 64, 4, 7, 0.615, and 001 01 and got 1.876 so i figured out that that is half of 64%. So that gave me an idea that Taylor was closest to the table.

4 0
3 years ago
What is the first step in estimating 56×27
Law Incorporation [45]

The first step is to determine how accurate your estimation needs to be. Then create the iniatial estimate.

5 0
4 years ago
Which choice is equivalent to the quotient shown here when x is greater than or equal to 0?
Dima020 [189]

Answer: OPTION C

Step-by-step explanation:

Remember that:

\sqrt[n]{a^n}=a

And the Product of powers property establishes that:

a^m*a^n=a^{(mn)}

Rewrite the expression:

\frac{\sqrt{18x} }{\sqrt{32} }

Descompose 18 and 32 into their prime factors:

18=2*3*3=2*3^2\\32=2*2*2*2*2=2^5=2^4*2

Substitute into the expression, then:

\frac{\sqrt{(2*3^2)x} }{\sqrt{2^4*2} }

Finally,simplifying, you get:

\frac{3\sqrt{(2)x} }{2^2\sqrt{2} }=\frac{3\sqrt{2x}}{4\sqrt{2}}=\frac{(3)(\sqrt{x})(\sqrt{2})}{(4)(\sqrt{2})}= \frac{3\sqrt{x}}{4}

8 0
3 years ago
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