Question

The university bought a total of 2,200 computers. They bought 3 kinds of computers: HP, IBM, and Dell. The ratio of the number of HP computers to IBM to Dell is 2:3:6.Each HP computer costs $750. Each Dell computer costs 90% of the price of an HP computer. If the university spent a total of $1,650,000, what is the cost of each IBM computer?

Answer 1

Answer:

Cost of each IBM computer is $787.5

Step-by-step explanation:

Given

Ratio of the number of HP computers to IBM to Dell is 2:3:6.

Cost of HP computer = $750.

Cost of Dell computer costs 90% of the price of an HP computer.

Total Amount Spent = $1,650,000.

First, we need to calculate the cost of Dell computers

Cost of Dell Computers = 90% * Cost of HP computer

Cost of Dell Computers = 90% * $750

Cost of Dell Computers = $675

Then we calculate the number of each computer type;

For HP;

$\frac{2}{2+3+6}$ = $\frac{2}{11}$

Number of HP = $\frac{2}{11}$ * 2200

Number of HP = 400

For Dell;

$\frac{3}{2+3+6}$ = $\frac{3}{11}$

Number of Dell = $\frac{3}{11}$ * 2200

Number of Dell = 600

For IBM;

$\frac{6}{2+3+6}$ = $\frac{6}{11}$

Number of Dell = $\frac{6}{12}$ * 2200

Number of Dell = 1200

So, the total amount spent on each type of computer is;

For HP = 400 * 750 = 300,000

For Dell = 600 * 675 = 405,000

Let x represent amount spent on each IBM computer

For IBM = 1200 * x = 1200x

Total = 300000 + 405000 + 1200x = $1,650,000.

$705,000 + 1200x = $1,650,000.

1200x = $1,650,000 - $705,000

1200x = $945,000

x = $945,000/1200

x = $787.5

Cost of each IBM computer is $787.5