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MakcuM [25]
3 years ago
6

Find two positive numbers whose difference is 2828 and whose product is 39003900.

Mathematics
1 answer:
Anastasy [175]3 years ago
7 0
If the question is:
"<span>Find two positive numbers whose difference is 28 and whose product is 3900</span>"

If the larger number is x, then
x-3900/x=28
multiply by x and transpose
x^2-28x-3900=0
Factor
(x+78)(x-50)=0
Using the zero product property,
x=-78 or x=50, ie.  x=50, y=-78

NOTE: if question requires both numbers be positive, there is no solution.
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<h2><em><u>Option</u></em><em><u> </u></em><em><u>B</u></em></h2><h2><em><u>x</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>50</u></em><em><u>°</u></em><em><u> </u></em></h2>

Step-by-step explanation:

<em><u>By</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>condition</u></em><em><u>, </u></em>

25° + 105° + x = 180° <em>[</em><em>Angle</em><em> </em><em>sum</em><em> </em><em>property</em><em> </em><em>of</em><em> </em><em>triangle</em><em>]</em>

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