Answer:
Rate of change for the linear relationship modeled is 
Step-by-step explanation:
As the there is a linear relationship in the points, so all these points will be on a single straight line. Hence the slope will be same throughout all the points.
We know that, the slope of the line joining (x₁, y₁) and (x₂, y₂) is,
Putting the points as (-1, 10) and (1, 9), we get
Rate of change is the slope of the line joining all these points.
The linear function that calculates the expected distance from the sun of the Voyager-2 spacecraft in x years after 1990 is given by:
y = 3.3x + 30.6.
<h3>What is a linear function?</h3>
A linear function is modeled by:
y = mx + b
In which:
- m is the slope, which is the rate of change, that is, by how much y changes when x changes by 1.
- b is the y-intercept, which is the value of y when x = 0, and can also be interpreted as the initial value of the function.
In this problem, we have that the distance increases 33 AU each 10 years, hence the slope is given by:
m = 33/10 = 3.3.
Hence:
y = 3.3x + b.
When x = 28, y = 123, hence we use it to find b as follows:
123 = 3.3(28) + b
b = 30.6.
Hence equation to calculate the expected distance from the sun of the Voyager-2 spacecraft in x years after 1990 is given by:
y = 3.3x + 30.6.
More can be learned about linear functions at brainly.com/question/24808124
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Answer:The better buy Option is A
Step-by-step explanation:
Answer:Two such terms are 7x^3*y^9 and -3x*y^5
Their quotient is
7x^3*y^9
--------------
-3x*y^5
This can be simplified as follows:
The numerical coefficients become -7/3.
x^3/x = x^3*x^1 = x^(3 - 1) = x^2 (we subtract the exponent of x in the denominator from the exponent of x in the numerator).
Next, y^9*y^5 = y^4.
The quotient in final reduced form is then (-7/3)x^2*y^4
