A. given
b. distributive property (a(b+c)=ab+ac)
c. addition or commutative property (a+b=b+a)
d. subtraction property of equality (if a=b, then a-c=b-c)
e. division property of equality (if a=b, then a/c=b/c)
f. equality property (if a=b, then b=a)
Answer:
The answer is below
Step-by-step explanation:
The distance between two points A(x₁, y₁) and B(x₂, y₂) on the coordinate plane is given by:
Point J is at (-3, 3), point K is at (4, 3) and point L is at (1, -1). Hence:
The distance between K and L = KL = 
The distance between J and L = JL = 
The distance between K and J = JK = 
Therefore, the perimeter of triangle JKL is:
Perimeter = KL + JL + JK = 5 + 4√2 + 7 = 17.66 units
SINCE THEY ALL PAID EQUALLY, IT HAS TO BE A MULTIPLE OF 3. BY TRIAL AND ERROR, THE FIRST POSSIBLE MATCH IS 3.. SINCE 132 IS DIVISIBLE BY 11
Answer:
$3800
Step-by-step explanation:
When simple interest is added to the principal amount, the sum increases linearly with time. Essentially, you are asked for the y-intercept of a line that goes through the points (2, 6200) and (3, 7400). You can use the 2-point form of the equation of a line to find it:
y = (y2 -y1)/(x2 -x1)(x -x1) +y1
y = (7400 -6200)/(3 -2)(x -2) +6200 . . . . fill in given points
y = 1200(x -2) +6200 . . . . . . . . . simplify some
y = 1200x -2400 +6200 . . . . . . simplify more
y = 1200x +3800 . . . . . . . . . . . . . completely simplify
When the number of years (x) is zero, the amount is 3800. The principal is $3800.
_____
The account is earning $1200 per year on a principal of $3800. The interest rate is about 31.6%, an unusually high value.
_____
<em>Alternate solution</em>
You can recognize that the interest earned in one year is 7400 -6200 = 1200. Since this is simple interest, the amount of interest earned each year is the same, so in 3 years, the account has earned 3×$1200 = $3600 in interest. Then the original principal amount must be ...
$7400 -3600 = $3800 . . . . . principal amount
