Question

The approximate distance between K and L is units. The approximate distance between L and J is units. If you join all three points, then the perimeter of the triangle created is approximately units.

Answer 1

Answer:

The answer is below

Step-by-step explanation:

The distance between two points A(x₁, y₁) and B(x₂, y₂) on the coordinate plane is given by:

$AB=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Point J is at (-3, 3), point K is at (4, 3) and point L is at (1, -1). Hence:

The distance between K and L = KL = $\sqrt{(-1-3)^2+(1-4)^2} =5\ units$

The distance between J and L = JL = $\sqrt{(-1-3)^2+(1-(-3))^2} =4\sqrt{2} \ units$

The distance between K and J = JK = $\sqrt{(3-3)^2+(-3-4)^2} =7\ units$

Therefore, the perimeter of triangle JKL is:

Perimeter = KL + JL + JK = 5 + 4√2 + 7 = 17.66 units